Answer:
A score of 150.25 is necessary to reach the 75th percentile.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.
This means that 
What score is necessary to reach the 75th percentile?
This is X when Z has a pvalue of 0.75, so X when Z = 0.675.
A score of 150.25 is necessary to reach the 75th percentile.
Answer: 77% of the apples will contain at least 2.36 ounces of juice.
Step-by-step explanation:
Since the amount of juice squeezed from each of these apples is approximately normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the amount of juice squeezed in ounces.
µ = mean
σ = standard deviation
From the information given,
µ = 2.25 ounces
σ = 0.15 ounce
Looking at the normal distribution table, the z score corresponding 77%(77/100 = 0.77) is 0.74
Therefore, the number of ounces of juice, x will be
0.74 = (x - 2.25)/0.15
Cross multiplying, it becomes
x - 2.25 = 0.74 × 0.15
x - 2.25 = 0.111
x = 0.111 + 2.25
x = 2.36
Answer:
theb correct answer is d VHow does your body’s flexibility naturally change as you age?
Step-by-step explanation:
Your answers are: Option A, because the investment will have a greater value.
And..... Option B, The investment will have a greater value.
