2 years ago

Which functions are invertible Select each correct answer

Mathematics

1 answer:

EastWind [94]2 years ago

4 0

Answer:

the top two

Step-by-step explanation:

For a function to be invertible, it must pass the "horizontal line test." That is, there can be no horizontal line that will intersect the graph in more than one place. The bottom two graphs fail this test, so do not represent invertible functions.

The two top graphs show invertible functions.

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Show that a sequence {sn} coverages to a limit L if and only if the sequence {sn-L} coverages to zero.

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Let ${s_n}_{n\in\Bbb N}$ be a sequence that converges to $L$ . This means for any $\varepsilon>0$ , there is some $N$ such that $|s_n-L|$ for all $n>N$ . From this inequality we see that $|(s_n-L)-0|$ , so it follows that $s_n-L\to0$ .

On the other hand, let ${s_n-L}$ be a sequence that converges to 0. This means $|(s_n-L)-0|$ for all large enough $n$ , and we get the simpler inequality for free, $|s_n-L|$ , so it follows that $s_n\to L$ .