Given: ∠KJL and ∠KML intercept arc KL. Prove: m∠KJL = m∠KML
2 answers:
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Area = 
so if the diameter is 16, radius (r) = 8
3.14 * 8^2 = 3.14*64 = 200.96 is the approximate area
If you're looking for the answer in terms of pi, 64pi is the answer.
3.14 * 8^2 = 3.14*64 = 200.96 is the approximate area
If you're looking for the answer in terms of pi, 64pi is the answer.