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3 years ago

Given: ∠KJL and ∠KML intercept arc KL. Prove: m∠KJL = m∠KML

Mathematics

2 answers:

Marizza181 [45]3 years ago

7 0

I think it proved by the arc intercepting kl making it an interior alternate angle which means it equal to each other

Flura [38]3 years ago

6 0

Answer:

1. inscribed angle thm.

2. inscribed angle thm.

3. substitution property

Step-by-step explanation:

These are the answers for ed

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Central Boulevard runs diagonally across town as shown below. The distance from Eastern Avenue to Western Avenue along South Str

murzikaleks [220]

The locations of the streets describes a right triangle with the angles 30 degrees and 60 degrees between them and the length of the side opposite the 60 degrees angle is $4\sqrt{3} \, miles$

a.) To find the distance form North Street to South Street along Eastern Avenue, we find the length of the side opposite the 30 degrees angle.

Using sine rule, we recall that the sine rule states that
$\frac{\sin{A}}{a} = \frac{\sin{B}}{b}$
where:
a = $4\sqrt{3}$
A = 60 degrees
B = 30 degrees
b = unknown
$\frac{\sin{60^o}}{4\sqrt{3}} = \frac{\sin{30^o}}{b} \\ b=\frac{4\sqrt{3} \sin{30^o}}{\sin{60^o}}= \frac{3.4641}{0.8660} = 4 \, miles$

Therefore, the distance form North Street to South Street along Eastern Avenue is 4 miles.

b.) To find the distance from North Street to South Street along Central Boulevard we find the length of the hypothenus of the right triangle.

Using pythagoras theorem, we recall that the pythagoras states that
$c^2=a^2+b^2$
where:
a = $4\sqrt{3}$
b = 4 miles
c = hypothenus = unknown
$c^2=\left(4 \sqrt{3} \right)^2+4^2=48+16=64 \\ c= \sqrt{64} =8 \, miles$

Therefore, the distance from North Street to South Street along Central Boulevard is 8 miles

5 0

3 years ago

Answer these two questions

AVprozaik [17]

For PART A: the height of the pole in the right angle triangle is 30 ft and the correct option is C

For PART B: the lenght of wire 1 in the right angle triangle is 45 ft and the right option is D

<h3 /><h3>What is a right angle triangle?</h3>

A right-angled triangle is a polygon of three sides having one angle as 90 degrees(right angle).

Part A

To calculate the height of the pole in the right angle triangle, we use the formula below.

Formula:

tan∅ = opposite/adjacent

From the diagram,

Given:

∅ = 41°
Opposite = Height of the pole = P
Adjacent = 34 ft

Substitute these values into equation 1 and solve for P

tan41° = P/34
P = 34×tan41°
P = 29.55
P ≈ 30 ft

Part B

Similarly, fine the length of wire 1, we use the formula below.

Formula:

cos∅ = Adjacent/Hypotenus.......... Equation 2

From the diagram,

Given:

Hypotenus = Wire 1 = x
∅ = 41°
Adjacent = 34 ft

Substitute these values into equation 2 and solve for x

cos41° = 34/x
x = 34/cos41°
x = 45.05
x ≈ 45 ft

Hence, the height of the pole is 30 ft and the lenght of wire 1 is 45 ft.

Learn more about right angle triangle here: brainly.com/question/64787

#SPJ1

5 0

1 year ago

What is the product of 4(8x + 5).

Andrei [34K]

We can solve this by distributing

$4(8x+5)$

Now, distribute the 4 to both 8x and 5.

$32x+20$

That's your answer!

6 0

2 years ago

8k^4 -3k^2 multiplied by 5k^2

S_A_V [24]

Answer: 40k⁶-15k⁴

Step-by-step explanation:

$(8k^4-3k^2)(5k^2)=\\\\8k^4(5k^2)-3k^2(5k^2)=\\\\8(5)(k^{4+2})-3(5)(k^{2+2})=\\\\40k^6-15k^4$

6 0

2 years ago

Read 2 more answers

What number would complete the pattern 16 4 11 36 9 27 44 11

sasho [114]

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8 0

3 years ago