I think the correct answer from the choices listed above is option C. If Sam goes to the View menu, clicks Toolbars, and then clicks Picture, then the picture toolbar will appear. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The iteration variable begins counting with 0 or 1.
As you know the iteration mostly done in the looping. For example, for loop and foreach loop and while loop, etc.
It depends upon you that from where you can begin the counting. You can begin counting either from zero or from one.
For example: this program counts 0 to 9.
<em>int total=0;</em>
<em>for(int i=0; i>10;i++)</em>
<em>{</em>
<em>total = total+i;</em>
<em>}</em>
Let's suppose, if you want to begin counting from 1, then the loop should look like below:
<em>int total=0;</em>
<em>for(int i=1; i>10;i++)</em>
<em>{</em>
<em>total = total+i;</em>
<em>}</em>
You are going to select 5 keyboards, from a set of 25 defective keyboards. When you select the first keyboard it may be have either electrical deffects or mechanical deffect, this is two possibilities. The same happens with the second, third, fourth and fifth selection. Then each selection has 2 different possibilities, and the number of possibilities are: 2*2*2*2*2 = 32.
But that is considering that the order matters. This is that it is different that the first has electrical deffects and the others have mechanical defects than the second has mechanical electrical deffects and the other has mechanical deffects.
If you the order is not relevant, then the only different outcomes are:
1) 5 with electrical deffects
2) 4 with electrical deffects and 1 with mechanical deffects
3) 3 with electrical deffects and 2 with mechanical deffects
4) 2 with electrical deffects and 3 with mechanical deffects
5) 1 with electrical deffects and 4 with mechanical deffects
5) 5 with mechanical deffects.
In this case the answer is 6 different ways.
Answer: 6
