Point slope form follows the equation y-y₁=m(x-x₁), so we want it to look like that. Starting off with m, or the slope, we can find this using your two points with the formula
![\frac{ y_{1} -y_{2} }{ x_{1} - x_{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20y_%7B1%7D%20%20-y_%7B2%7D%20%7D%7B%20x_%7B1%7D%20-%20x_%7B2%7D%20%7D%20)
. Note that y₁ and x₁ are from the same point, but it does not matter which point you designate to be point 1 and point 2. Thus, we can plug our numbers in - the x value comes first in the equation, and the y value comes second, so we have
![\frac{5-2}{10-2} = \frac{3}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5-2%7D%7B10-2%7D%20%3D%20%5Cfrac%7B3%7D%7B5%7D%20)
as our slope. Keeping in mind that it does not matter which point is point 1 and which point is point 2, we go back to y-y₁=m(x-x₁) and plug a point in (I'll be using (10,5)). Note that x₁, m, and y₁ need to be plugged in, but x and y stay that way so that you can plug x or y values into the formula to find where exactly it is on the line. Thus, we have our point slope equation to be
![y- 5= \frac{3}{5} (x-10)](https://tex.z-dn.net/?f=y-%205%3D%20%5Cfrac%7B3%7D%7B5%7D%20%28x-10%29)
Feel free to ask further questions!
Answer:
solution is : x = -6 and x = 2
Step-by-step explanation:
<span><span /><span>In an observational study, During the discussion,
the author can indicates conclusion and explains the limitation of the study he
did.
This is where the author can give the scope and limitations of his study and
also to discuss what is the future use of his study. In introduction is where
he can write the reason why he studied his research, in methodology is where he
can write when , where and how he did his research and in result is where he
can state what problem his research answered or what’s the edge of his
research.</span></span>
Answer:
x = +2√21 and y = +2√30
Step-by-step explanation:
The two marked sides of the smaller triangle are x and y. The third side has length equal to 14 - 8, or 6.
We can thus write two equations in x and y:
x^2 = y^2 + 6^2
and
y 6
-- = ---
8 y
Solving the first equation for y^2 yields y^2 = 36 - x^2. Solving the second equation for y^2 yields 48. Thus 36 - x^2 = 48, and
x^2 = 84. Thus, x = +√7*√4*√3, or x = +2√21.
We now find y. y^2 = 36 = x^2, which here becomes
y^2 = 36 + 4(21) = 36 + 84 = 120. Thus, y = +√4*√30, or y = +2√30.