Question

What is the answer please give i really help and no links

Answer 1

Answer:

$9\frac{57}{63}$

Step-by-step explanation:

First, we need to turn them into improper fractions:

$2\frac{4}{7}$ + $7\frac{3}{9}$

7 x 2 + 4

7 x 9 + 3

$\frac{18}{7}$ + $\frac{66}{9}$

Next, we need to find a common multiple of both 7 and 9

7, 14, 21, 28, 35, 42, 49, 56, 63

9, 18, 27, 36, 45, 54, 63

So the denomonator turns into 63.

We've multiplied the denomonater 9 times for the first fraction and 7 times for the second fraction, we therefore have to do the same to the numerator.

18 x 9 = 162

66 x 7 = 462

$\frac{162}{63}$ + $\frac{462}{63}$ = $\frac{624}{63}$

Next, we have to turn it back into a mixed number.

To work it out: 624 / 63 = 9 (1 s.f) <--- Mixed number.

9 x 63 = 567

624 - 567 = 57 (Working out the remainder.)

Combining them, the answer is therefore $9\frac{57}{63}$

Hope this helps and have a good day!