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2 years ago

What is b-2 = - 12 Ill give brainlist!

Mathematics

2 answers:

Ede4ka [16]2 years ago

5 0

Are you asking for what is B?

Cause B= -14

-14-2 = -12

I forgot when you subtract a negative from a negative number it turns into additionnnn T-T

mash [69]2 years ago

4 0

Answer:

-14

Step-by-step explanation:

-14 - 2 = - 12

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Hello , how to do 6(iii)?

Doss [256]

Answer:

$\displaystyle \frac{dS}{dt}=\frac{3}{50r}$

Step-by-step explanation:

Water is being pumped into an inflated rubber sphere at a constant rate of 0.03 cubic meters per second.

So, dV/dt = 0.03.

We want to show that dS/dt is directly proportional to 1/r.

In other words, we want to establish the relationship that dS/dt = k(1/r), where k is some constant.

First, the volume of a sphere V is given by:

$\displaystyle V=\frac{4}{3}\pi r^3$

Therefore:

$\displaystyle \frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

Next, the surface area of a sphere S is given by:

$\displaystyle S=4\pi r^2$

Therefore:

$\displaystyle \frac{dS}{dt}=8\pi r\frac{dr}{dt}$

We can divide both sides by 2:

$\displaystyle \frac{1}{2}\frac{dS}{dt}=4\pi r\frac{dr}{dt}$

We can substitute this into dV/dt. Rewriting:

$\displaystyle \frac{dV}{dt}=r\Big(4\pi r\frac{dr}{dt}\Big)$

So:

$\displaystyle \frac{dV}{dt}=\frac{1}{2}r\frac{dS}{dt}$

Since dV/dt = 0.03 or 3/100:

$\displaystyle \frac{3}{100}=\frac{1}{2}r\frac{dS}{dt}$

Therefore:

$\displaystyle \frac{dS}{dt}=\frac{3}{50r}=\frac{3}{50}\Big(\frac{1}{r}\Big)$

Where k = 3/50.

And we have shown that dS/dt is directly proportional to 1/r.

4 0

3 years ago

Evaluate the following expressions given x=6 and y=-3

Nana76 [90]

$\purple{5 \times 6 - 4 \times ( - 3)}$

$= 30 + 12$

$\blue{ = \boxed{42}}$

$\purple{ {6}^{2} + \frac{6}{ - 3} }$

$= 36 - 2$

$\blue{ = \boxed{34}}$

$\purple{(6 - 5 {)}^{3} + {( - 3)}^{2} }$

$= {1}^{3} + 9$

$= 1 + 9$

$\blue{ = \boxed{10}}$

Hope it helps

7 0

2 years ago

How do I solve X+5=54

Archy [21]

Answer:

x = 40

I hope this helps a little bit

6 0

2 years ago

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Mileage tests are conducted for a particular model of automobile. If a 98% confidence interval with a margin of error of 1 mile

Llana [10]

Answer: 37

Step-by-step explanation:

Given : Significance level : $\alpha:1-0.98=0.02$

Critical value : $z_{\alpha/2}=z_{0.01}=2.33$

margin of error : E= 1 mile per gallon

Population standard deviation: $\sigma=2.6$ miles per gallon.

We know that when the population standard deviation is known then the formula to find the sample size is given by :

$n=(\dfrac{z_{\alpha/2}\times \sigma}{E})^2$

$n=(\dfrac{(2.33)\times 2.6}{1})^2=36.699364\approx37$ [Round to the next whole number.]

Hence, the required number of automobiles should be used in the test = 37

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3 years ago

Help Meeeeeeee!!!!!!!!

vesna_86 [32]

Answer: 1st one

Step-by-step explanation:

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3 years ago