Answer:
The measure of one of the acute angles is 22 degrees, and the measure of the other acute angle is 68 degrees.
Step-by-step explanation:
The angles of a triangle add up to 180 degrees; we know this by the Sum of Angles of a Triangle Theorem.
Then one angle is marked as a right angle meaning it has a measure of 90 degrees.
Using this information and the labels on the diagram we can set up an equation:
x+3x+2+90=180
Now we can solve for x.
4x+92=180
4x=88
x=22 degrees
The measure of one of the acute angles is 22 degrees.
Now to solve for the measure of the other acute angle.
Subsitute the value of x first.
x=22
(3x+2)=?
3*22+2=68 degrees
The measure of the other acute angle is 68 degrees.
To find the equation of a line that is parallel to your original equation and goes through a certain point on a graph, here's what you need to know:
First you need to find the slope of your original equation.
To do that, you need to convert it to slope intercept form (y = mx+b).
Add the x over, and then divide everything by 5 to get the y by itself.
Here's what that would look like (without the small steps that I mentioned):
-x + 5y = 25
5y = x + 25
y = 1/5x + 5
That's the original equation rewritten in slope intercept form.
The m represents the slope, so this equation's slope is 1/5.
Because you are given a point, and now you have a slope, the best and easiest route is using point slope form.
I've seen different versions of the equation base but I prefer y - y(sub1) = m(x - x(sub1))
But since I can't use subscripts in this, I'll use the one with h and k. The h is the x value of the point, and the k is the y value.
(h,k)
Then just substitute the values in and solve for y.
y - k = m(x - h)
y + 5 = 1/5(x + 5)
y + 5 = 1/5x + 1
y = 1/5x - 4
Your final answer is
y = 1/5x - 4
You can double check by using a graph. If the slopes are the same, the lines should be parallel.
I hope that helps. If anything didn't make sense, feel free to ask me.
Answer: 21,875 sqm
Step-by-step explanation:
Step 1:
Find the gross area of the garden.
Square 150m = 22,500 sqm.
Step 2:
Find the area of the pool.
Square 25m = 625 sqm.
Step 3:
Subtract the area of the pool from the gross area of the garden
to find the net area of the garden.
22,500 - 625 = 21,875 sqm.
Warning:
Do not subtract the side length of the swimming pool from the side length
of the garden before squaring.
I would say that the answer is B
