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k0ka [10]
2 years ago
7

(I will give brainliest) Please HELP me!!

Mathematics
2 answers:
dusya [7]2 years ago
7 0

Answer:

1.3x - 5 = 25 \\ 3x = 25 + 5 \\ 3x = 30 \\ x =  \frac{30}{3}  = 10 \\   \\  - 4x +6 = 26  \\  - 4x = 26 - 6  \\  - 4x = 20 \\  x =  -  \frac{20}{4}  =  - 5 \\  \\ 7x - 8 = 50 \\ 7x = 50 + 8 \\ 7x = 58 \\ x =  \frac{58}{7}  = 8

\sf{hope \: it \: helps}

Salsk061 [2.6K]2 years ago
5 0

Answer:

1) Value of x = 10

2) Valye of x = -5

3) Valye of x = -6

Step-by-step explanation:

<h3><u>Concept</u> :</h3>

Here, we will use the below following steps to find a solution using the transposition method:

  • <u>Step 1</u> :- we will Identify the variables and constants in the given simple equation.
  • <u>Step 2</u> :- then we Simplify the equation in LHS and RHS.
  • <u>Step 3</u> :- Transpose or shift the term on the other side to solve the equation further simplest.
  • <u>Step 4</u> :- Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.
  • <u>Step 5</u> :- Then the result will be the solution for the given linear equation.

\begin{gathered}\end{gathered}

<h3><u>Solution</u> :</h3>

1) 3x - 5 = 25

\twoheadrightarrow{\sf{3x - 5 = 25}}

\twoheadrightarrow{\sf{3x  = 25 + 5}}

\twoheadrightarrow{\sf{3x  = 30}}

\twoheadrightarrow{\sf{x  = \dfrac{30}{3} }}

\twoheadrightarrow{\sf{x  = \cancel{\dfrac{30}{3}}}}

\twoheadrightarrow{\sf{x  = 10}}

\star{\underline{\boxed{\bf{\red{x  = 10}}}}}

Hence, the value of x is 10.

\begin{gathered}\end{gathered}

2) -4x + 6 = 26

\twoheadrightarrow{\sf{ - 4x +  6= 26}}

\twoheadrightarrow{\sf{ - 4x= 26 - 6}}

\twoheadrightarrow{\sf{ - 4x= 20}}

\twoheadrightarrow{\sf{x= \dfrac{20}{ - 4}}}

\twoheadrightarrow{\sf{x=  \cancel{\dfrac{20}{ - 4}}}}

\twoheadrightarrow{\sf{x=   - 5}}

\star{\underline{\boxed{\bf{\red{x  =  - 5}}}}}

Hebce, the value of x is -5.

\begin{gathered}\end{gathered}

3) 7x - 8 = -50

\twoheadrightarrow{\sf{7x - 8 =  - 50}}

\twoheadrightarrow{\sf{7x =  - 50 + 8}}

\twoheadrightarrow{\sf{7x =  - 42}}

\twoheadrightarrow{\sf{x = \dfrac{ - 42}{7} }}

\twoheadrightarrow{\sf{x = \cancel{\dfrac{ - 42}{7}}}}

\twoheadrightarrow{\sf{x =  - 6}}

\star{\underline{\boxed{\bf{\red{x  =  - 6}}}}}

Hence, the value of x is -6.

\rule{300}{1.5}

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