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2 years ago

what is the equation of a line that is perpendicular to y=5 and that passes through the point (-7, -5)

Mathematics

1 answer:

Arlecino [84]2 years ago

3 0

Answer:

x = -7

Step-by-step explanation:

The vertical line through (-7, -5) will be of the form ...

x = constant

To make the line go through the given point, the constant must be the x-coordinate of that point:

x= -7

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user100 [1]

Answer:

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3 years ago

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Pavel [41]

Answer:

Yes

Step-by-step explanation:

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Since multiplication is commutative order is not important, that is

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3 years ago

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DerKrebs [107]

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8 0

3 years ago

Consider the following theorem. Theorem If f is integrable on [a, b], then b a f(x) dx = lim n→[infinity] n i = 1 f(xi)Δx where

mel-nik [20]

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[1, 1 + 8/n], [1 + 8/n, 1 + 16/n], [1 + 16/n, 1 + 24/n], …, [1 + 8 (n - 1)/n, 9]

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1 + 8/n (i - 1)

Then we approximate the definite integral by the sum of the areas of n rectangles with length 8/n and height $f(x_i)$ :

$\displaystyle \int_1^9 (x^2-4x+6) \,\mathrm dx \approx \sum_{i=1}^n \frac8n\left(\left(1+\frac8n(i-1)\right)^2-4\left(1+\frac8n(i-1)\right)+6\right)$

Take the limit as n approaches infinity and the approximation becomes exact. So we have

$\displaystyle \int_1^9 (x^2-4x+6) \,\mathrm dx = \lim_{n\to\infty} \sum_{i=1}^n \frac8n\left(\left(1+\frac8n(i-1)\right)^2-4\left(1+\frac8n(i-1)\right)+6\right) \\\\ = \lim_{n\to\infty} \frac8n \sum_{i=1}^n \left(1+\frac{16}n(i-1)+\frac{64}{n^2}(i-1)^2-4-\frac{32}n(i-1)+6\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \sum_{i=1}^n \left(64(i-1)^2-16n(i-1)+3n^2\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \sum_{i=0}^{n-1} \left(64i^2-16ni+3n^2\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \left(64\sum_{i=0}^{n-1}i^2 - 16n\sum_{i=0}^{n-1}i + 3n^2\sum{i=0}^{n-1}1\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \left(\frac{64(2n-1)n(n-1)}{6} - \frac{16n^2(n-1)}{2} + 3n^3\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \left(\frac{49n^3}3-24n^2+\frac{32n}3\right) \\\\= \lim_{n\to\infty} \frac{8\left(49n^2-72n+32\right)}{3n^2} = \boxed{\frac{392}3}$

3 0

3 years ago

Subtract. (3x+3)–(3x+3)

Alex73 [517]

your answer will be 0.

5 0

3 years ago

what is the equation of a line that is perpendicular to y=5 and that passes through the point (-7, -5)​

what is the equation of a line that is perpendicular to y=5 and that passes through the point (-7, -5)