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Schach [20]
3 years ago
10

If you have five red balls and five blue balls in a jar what’s the probability of the first ball being red?

Mathematics
2 answers:
rosijanka [135]3 years ago
8 0

Answer:

red balls = 5

blue balls = 5

total balls = 5 blue+5 red

= 10

p(first \: ball \: being \: red) =  \frac{red \: balls}{total \: balls}

p(first \: ball \: being \: red) =  \frac{5}{10}  =  \frac{1}{2}

andrey2020 [161]3 years ago
7 0

Answer:

Step-by-step explanation:

Total number of red balls = 5

Total number of blue balls = 5

Total number of balls in jar = 5 + 5

                                             = 10

Probability of the first ball being red = total number of the red ball/total number of balls in the jar

                                                             = \frac{5}{10}

                                                             = \frac{1}{2}

Therefore, the probability of the first ball being red = \frac{1}{2}, 50% or 0.5 (in any way you are instructed to write it in)

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The given dimensions of 9.5, 6, 7, and 6.5 cm gives the following

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<h3>How can the area and perimeter of the trapezium be found?</h3>

The perimeter of a trapezoid is given as follows;

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Learn more about the area and perimeter of geometric shapes here:

brainly.com/question/359059

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