The value of x {0 < x < (π/2)} satisfying (cos x / cosec x + 1) + (cos x / cosec x-1) = 2 is x = π/4.
Since cos x /(cosec x + 1) + cos x /(cosec x - 1) = 2
Taking the L.C.M (cosecx + 1)(cosecx - 1), we have
[cosx(cosecx - 1) + cosx(cosecx + 1)]/(cosecx + 1)(cosecx - 1) = 2
[cosxcosecx - cosx + cosxcosecx + cosx]/(cosec²x - 1²) = 2
[cosx/sinx - cosx + cosx/sinx + cosx]/(cosec²x - 1²) = 2
[cotx - cosx + cotx + cosx]/(cosec²x - 1) = 2
collecting like terms, we have
[cotx + cotx + cosx - cosx ]/(cosec²x - 1) = 2
[2cotx + 0]/(cosec²x - 1) = 2
2cotx/(cosec²x - 1) = 2
cotx/(cosec²x - 1) = 1
Since cot²x + 1 = cosec²x ⇒ cot²x = cosec²x - 1
So, cotx/(cosec²x - 1) = 1
cotx/cot²x = 1
1/cotx = 1
tanx = 1
Taking inverse tan of both sides, we have
x = tan⁻¹(1)
x = 45°
x = 45 × π/180
x = π/4
So, the value of x {0 < x < (π/2)} satisfying (cos x / cosec x + 1) + (cos x / cosec x-1) = 2 is x = π/4.
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