<h3>
Answer: (n-1)^2</h3>
This is because we have a list of perfect squares 0,1,4,9,...
We use n-1 in place of n because we're shifting things one spot to the left, since we start at 0 instead of 1.
In other words, if the answer was n^2, then the first term would be 1^2 = 1, the second term would be 2^2 = 4, and so on. But again, we started with 0^2 = 0, so that's why we need the n-1 shift.
You can confirm this is the case by plugging n = 1 into (n-1)^2 and you should find the result is 0^2 = 0. Similarly, if you tried n = 2, you should get 1^2 = 1, and so on. It appears you already wrote the answer when you wrote "Mark Scheme".
All of this only applies to sequence A.
side note: n is some positive whole number.
The whole-number factors of 23 are 1 and 23 .
1. If the line that we are searching for is perpendicular to the line y = -4x, this means that the gradient of our line and the gradient of the perpendicular line will multiply to give -1. Thus if we call the gradient of our line m, then:
m*(-4) = -1
-4m = -1
m = 1/4
2. Since we know that m = 1/4 and we have a point (2,6) on our line, we can use the formula y - y1 = m(x - x1) to find the equation of our line, where (x1, y1) is the coordinates of a point on the line. Thus:
y - y1 = m(x - x1)
y - 6 = (1/4)(x - 2)
y - 6 = (1/4)x - 2/4 (Expand (1/4)(x - 2))
y = (1/4)x - 1/2 + 6 (Simplify 2/4 and add 6 to each side)
y = (1/4)x + 11/2 (Evaluate -1/2 + 6)
Slope-intercept form is given by y = mx + c. As our equation is already in this form, there is nothing more to do. Thus, the answer is y = (1/4)x + 11/2
Answer:
Option B
Step-by-step explanation:
<WXV = <YXZ (Vertically opposite angles are congruent.)
