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3 years ago

How do you explain if something IS NOT a perfect square/ square number?

Mathematics

2 answers:

mariarad [96]3 years ago

6 0

Answer:

A square number cannot be a perfect number. 0, 1, 5, 14, 30, 55, 91, 140, 204, 285, 385, 506, 650, 819, 1015, 1240, 1496, 1785, 2109, 2470, 2870, 3311, 3795, 4324, 4900, 5525, 6201... The sum of the first odd integers, beginning with one, is a perfect square: 1, 1 + 3, 1 + 3 + 5, 1 + 3 + 5 + 7, etc.

Step-by-step explanation:

Tom [10]3 years ago

6 0

Answer: Suppose √64 = 8, Here 64 is the perfect square number. It gives 8 as the answer which is a natural number. So we call 64 as a perfect square number. Based on this I conclude the numbers which give decimal form an answer when they are under root those are considered to be not a perfect square number.

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Alona [7]

Answer:

The lower limit is 75.04

The upper limit is 78.96

Step-by-step explanation:

From the question we are told that

The sample size is $n = 25$

The sample mean is $\= x = 77$

The standard deviation is $\sigma = 5$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = (100 - 95)\%$

$\alpha = 0.05$

The critical value for $\frac{\alpha }{2}$ obtained from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96* \frac{5 }{\sqrt{25} }$

=> $E = 1.96$

The 95% confidence interval is mathematically represented as

$\= x -E < \mu < \= x +E$

=> $77 - 1.96 < \mu < 77 + 1.96$

=> $75.04 < \mu < 78.96$

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3 years ago

What dose valuable mean

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Murrr4er [49]

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3 years ago

Frank started an assignment at 6:26 PM and finished it at 7:44 PM. How long did it take him? Give your answer in minutes.

Svet_ta [14]

7.44-6.26=1.18
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2 years ago

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A particle is moving on a straight line in such a way that its velocity v is given by v ( t ) = 2 t + 1 for 0 ≤ t ≤ 5 where t is

Lady_Fox [76]

Answer:

The total distance traveled by the particle is S = 30.

Step-by-step explanation:

Given that velocity,

v(t) = 2t + 1

To find the total distance travel, we integrate the velocity function, v(t), to obtain the distance function s(t), and evaluate the resulting distance at the interval given. That is at t = 0 to t = 5.

Integrating v(t) with respect to t, we have

s(t) = t² + t + C.

At t = 5

s(5) = 5² + 5 + C

= 25 + 5 + C

= 30 + C

At t = 0

S(0) = 0 + 0 + C

= C

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S(5) - S(0)

= 30 + C - C

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