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DIA [1.3K]
3 years ago
13

Please help me :(NO LINKS PLEASE​

Mathematics
2 answers:
liubo4ka [24]3 years ago
6 0

Answer:

Option A

Step-by-step explanation:

<u>Given equation is:</u>

x^2+1=2x-3

Setting it up as a quadratic equation.

x^2+1-2x+3=0\\\\x^2-2x+4=0

Comparing it with quadratic equation ax^2+bx+c=0, we get:

a = 1 , b = -2 , c = 4

<u>Putting the values in quadratic equation:</u>

\displaystyle x = \frac{-b +-\sqrt{b^2-4ac} }{2a} \\\\x = \frac{-(-2)+-\sqrt{(-2)^2-4(1)(4)}  }{2(1)}

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
sertanlavr [38]3 years ago
3 0

Answer:

A

Step-by-step explanation:

a = 1, b = -2, and c =4

d = -b +- sqrt (b^2 - 4*a*b)

= - (-2) +- sqrt ((-2)^2 - 4*1*4)

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