Question

Please help me :(NO LINKS PLEASE​

Answer 1

Answer:

Option A

Step-by-step explanation:

Given equation is:

$x^2+1=2x-3$

Setting it up as a quadratic equation.

$x^2+1-2x+3=0\\\\x^2-2x+4=0$

Comparing it with quadratic equation $ax^2+bx+c=0$, we get:

a = 1 , b = -2 , c = 4

Putting the values in quadratic equation:

$\displaystyle x = \frac{-b +-\sqrt{b^2-4ac} }{2a} \\\\x = \frac{-(-2)+-\sqrt{(-2)^2-4(1)(4)} }{2(1)}$

$\rule[225]{225}{2}$

Hope this helped!

~AH1807

Answer 2

Answer:

A

Step-by-step explanation:

a = 1, b = -2, and c =4

d = -b +- sqrt (b^2 - 4*a*b)

= - (-2) +- sqrt ((-2)^2 - 4*1*4)