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DIA [1.3K]
3 years ago
13

Please help me :(NO LINKS PLEASE​

Mathematics
2 answers:
liubo4ka [24]3 years ago
6 0

Answer:

Option A

Step-by-step explanation:

<u>Given equation is:</u>

x^2+1=2x-3

Setting it up as a quadratic equation.

x^2+1-2x+3=0\\\\x^2-2x+4=0

Comparing it with quadratic equation ax^2+bx+c=0, we get:

a = 1 , b = -2 , c = 4

<u>Putting the values in quadratic equation:</u>

\displaystyle x = \frac{-b +-\sqrt{b^2-4ac} }{2a} \\\\x = \frac{-(-2)+-\sqrt{(-2)^2-4(1)(4)}  }{2(1)}

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
sertanlavr [38]3 years ago
3 0

Answer:

A

Step-by-step explanation:

a = 1, b = -2, and c =4

d = -b +- sqrt (b^2 - 4*a*b)

= - (-2) +- sqrt ((-2)^2 - 4*1*4)

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Maths question please help !! thank u :)​
nikdorinn [45]

Answer:

1350m

Step-by-step explanation:

Let the distance ran by Denise, Farah and Elaine be D, F and E meters respectively.

From the given information,

D= ⅔(E +F) -----(1)

E= ½(D +F) -----(2)

Let's get rid of the fraction so the equations are much easier to work with.

From (1):

3D= 2(E +F) <em>(Multiply both sides by 3)</em>

3D= 2E +2F -----(3) <em>(</em><em>Expand</em><em>)</em>

From (2):

2E= D +F -----(4)

Substitute (4) into (3):

3D= D +F +2F

3D -D= 3F

2D= 3F

Given that Farah ran 360m, F= 360.

2D= 3(360)

2D= 1080

D= 1080 ÷2

D= 540

2E= D +F

2E= 540 +360

2E= 900

E= 900 ÷2

E= 450

Total distance the 3 girls ran

= D +F +E

= 540 +360 +450

= 1350m

Alternatively, you could start by substituting F= 360 to equations (1) and (2).

6 0
3 years ago
Which of the following values are in the range of the function graphed below?
Dafna1 [17]

Answer:

A. 1

Step-by-step explanation:

I see only one red function line in the graph. this line represents the simple function y = 1, for x in the interval [-2,1].

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this function has only one possible value for y : 1

so, only A applies.

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