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2 years ago

Directions: In your own words talk about the similarities and differences in angles?

Mathematics

1 answer:

AlladinOne [14]2 years ago

4 0

Revolutionary is the answer

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At the end of the school year a school system has a table with the total absences and tardies in its 10 schools what is the best

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2 years ago

Which of the following illustrates the truth value of the given conjunction?

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an integer is a rational number sometimes(eg.17=17/1) but not always.

a rational number can be written in the form p/q where p and q are integers.

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3 years ago

Eight more than twice a number is equal to ten less than five times the number. Let n represent the number. Write an equation th

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2 years ago

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Jen factored x² - 4x - 21 as (x - 3)(x + 7) What did she do wrong?

alexgriva [62]

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She didn't put the sign's in the proper place, it should be ( x + 3 ) ( x - 7 )

Step-by-step explanation:

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3 years ago

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The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

Anettt [7]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

Total number of cases = 15

Required probability is $\frac{8}{15}$ .

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3 years ago