If i did the math right it would be (C)
The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
Read more about inverse functions at:
brainly.com/question/14391067
#SPJ1
3,162 x 10 = 31,620, you just add one zero
Answer: 4/5
Step-by-step explanation:
Step 1: Put the percent over 100
- 80/100
Simplify it by dividing both the numerator and denominator by a common factor, aka 10
- 80/10 - 8
100/10 - 10
- 8/10
Simplify it again by dividing both the numerator and denominator by a second common factor, aka 2
= 8/2 - 4
10/2 - 5
- 4/5
Cannot be simplified any further.
