AB ≅CD, FA ≅ED

25 points! pls show work if can!!!!!!!!

Nataliya [291]

Answer: 8.4

Step-by-step explanation:

15-6.6

3 0

3 years ago

Read 2 more answers

Help for 15 points!! AND brainliest answers

Ede4ka [16]

Unit price for smaller bottle = 2.19 / 13.5 = $0.16 per ounce

For larger bottle its 5.37 / 29.2 = $0.18 per ounce

( to the nearest cent).

The better buy is the 13.5 ounce bottle

6 0

3 years ago

There are 8 members on a board of directors. If they must form a subcommittee of 5 members, how many different subcommittee are

Assoli18 [71]

56 different sub-committees are possible

Step-by-step explanation:

When the selection has to be made without order, combinations are used.

The formula for combination is:

$C(n,r) = \frac{n!}{r!(n-r)!}$

Here,

Total members = n = 8

Members to be selected = r = 5

So,

$C(8,5) = \frac{8!}{5!(8-5)!}\\= \frac{8!}{5!}\\=56\ ways$

Hence,

56 different sub-committees are possible

Keywords: Combinations, Selection

Learn more about combinations at:

#LearnwithBrainly

3 0

3 years ago

Please help ASAP.......

marta [7]

Answer:

The answer is x=10

Step-by-step explanation:

5/6x - 10 = 1/3x -5 multiple both sides by 6

5x - 60 = 2x -30 move the terms

5x - 2x = -30 +60

3x = 30 divide by 3

x = 10

3 0

3 years ago

Last year, a comprehensive report stated that 28% of businesses in the northeast of Ohio were considered highly profitable. This

Alik [6]

Answer:

$z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575$

$p_v =2*P(z>1.575)=0.115$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

Step-by-step explanation:

Data given and notation

n=50 represent the random sample taken

X=19 represent the businesses were highly profitable

$\hat p=\frac{19}{50}=0.38$ estimated proportion of businesses were highly profitable

$p_o=0.28$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of businesses were highly profitable is different from 0.28 or no, the system of hypothesis is.:

Null hypothesis: $p=0.28$

Alternative hypothesis: $p \neq 0.28$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.38 -0.28}{\sqrt{\frac{0.28(1-0.28)}{50}}}=1.575$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>1.575)=0.115$

So the p value obtained was a very high value and using the significance level given $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of businesses were highly profitable is not significantly different from 0.28 or 28%.

4 0

4 years ago