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Anon25 [30]
3 years ago
13

AB ≅CD, FA ≅ED

Mathematics
1 answer:
Rama09 [41]3 years ago
7 0
This answer is the SAS therom because you have 2 congruent sides and then you have the perpendicular bisector, which is a right angle
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Two drivers moving in opposite directions on an 18-mile circular racetrack cross each other at a certain point. If one of them h
Luda [366]

Answer:

They both would cross each other again in the next 5 minutes

Step-by-step explanation:

The first thing to do here is to calculate the lowest common multiple of the average speed of both drivers.

That would be the lowest common multiple of 1.2 miles per minute and 1.8 miles per minute.

That would be 3.6 miles per minute.

Now to get the time at which they would cross each other again, we simply divide the total distance around the circular track by the lowest common multiple of their average speed.

That would be 18/3.6 = 5

This means they would cross each other again in the next 5 minutes

5 0
4 years ago
Solve step by step.<br> 7x+4(4x-14)=59
ziro4ka [17]

Answer:

x = 5

Step-by-step explanation:

7x+16x-56=59

23x -56 = 5 9

2 3 x - 5 6 + 5 6 = 5 9 + 5 6

23x=115

\frac{23x}{23} = \frac{115}{23}

x = 5

4 0
3 years ago
I NEED HELP PLEAZE!!!!!!!!!!!!!!!! =(
scoundrel [369]

Answer:

x\sqrt{6y}/ 3y^{2}

Step-by-step explanation:

5 0
3 years ago
What are the solution(s) to the quadratic equation 50 - x2 = 0?
jekas [21]

Answer:

x = 5\sqrt{2}

Step-by-step explanation:

given, 50 - x^2 = 0

add x^2 to both sides, 50 = x^2

square root both sides, \sqrt{50}\\ = \sqrt{x^{2} }

simplify, 50 / 5 = 10 / 5 = 2

you have a pair of 5's, and a 2, 5\sqrt{2} = x

5 0
3 years ago
Triangle X Y Z is shown. The length of X Y is 9, the length of Y Z is 19, and the length of X Z is y. Angle X Y Z is 41 degrees.
nalin [4]

Answer:

y² = 9² + 19² - 2(9)(19)Cos (41°)

Step-by-step explanation:

Triangle X Y Z is shown.

The length of X Y is 9,

the length of Y Z is 19, and the length of X Z is y. Angle X Y Z is 41 degrees.

Law of cosines is given as:a²= b² + c² – 2bccos(A)

Applying this to Triangle XYZ, and since we are Solving for y

y² = x² + z² - 2xzCos Y

The length of X Y = x is 9,

the length of Y Z = y is 19

y²= 9² + 19² - 2(9 × 19)Cos (41°)

= y² = 9² + 19² - 2(9)(19)Cos (41°)

Option d is correct

6 0
3 years ago
Read 2 more answers
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