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n200080 [17]
2 years ago
5

Jacob wants to enlarge a 4 in. By 6 in. Photo so that the longer side will be 14 in. How long will the shorter side be? (MUST SH

OW WORK) HINT: Refer to your notes on Scale Drawings.
Mathematics
1 answer:
OleMash [197]2 years ago
8 0

Answer: 9.3 in.

Step-by-step explanation:

Jacob wants to enlarge the larger side of the photo which is the 6 in. part, to becomes 14 in.

This means that Jacob wants to increase the larger side by a scale factor of:

= Length of enlarged picture / Length of original

= 14 / 6

= 2.33

2.33 is therefore the scale factor.

The shorter side will also increase by this same scale factor:

= 4 * 2.33

= 9.3 in.

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andrew-mc [135]
So to answer you just have to substitute all the given choices into the formula and see which come out true.
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VYVEVSV

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4 0
3 years ago
Can someone please help me with this one? I’m very confused, how can you solve for the width if the problem doesn’t tell you wha
Marizza181 [45]

Answer:

A. (2x-3)/2

Step-by-step explanation:

Performing the long division indicated by the perimeter expression, you find ...

perimeter = (2x -3) + (10x +6)/(x^2 +2x)

Comparing this to the formula for the perimeter ...

perimeter = 2W +2L

where L is said to be of the form (ax +b)/(x^2 +2x)

we can match terms in the perimeter expression to see that ...

2W = 2x -3

2L = (10x +6)/(x^2 +2x)

The problem doesn't ask for it, but we can see that (a, b) = (5, 3). We can also see that ...

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4 0
3 years ago
(8,10) (-7,14) find the slope of the line through each pair of points.
DochEvi [55]
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8 0
3 years ago
Read 2 more answers
Solve for s <br><br> B=(s+z/4)h
viva [34]

<em>Greetings from Brasil...</em>

Isolating S:

B = [(S+Z)/4]·h

B/h = (S + Z)/4

<h2>S = (4B/h) - Z</h2>

4 0
3 years ago
Suppose the force acting on a column that helps to support a building is a normally distributed random variable X with mean valu
Sauron [17]

Answer:

(1) 0.4207

(2) 0.7799

Step-by-step explanation:

Given,

Mean value,

\mu = 15.0

Standard deviation,

\sigma = 1.25

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= 1- P(\frac{x-\mu}{\sigma} \leq \frac{17.5-\mu}{\sigma})

=1-P(z\leq \frac{17.5 - 15}{1.25})

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=1- 0.5793   ( By using z-score table )

= 0.4207

(2) P(14 ≤ X ≤ 18) = P(X ≤ 18) - P(X ≤ 14)

=P(z\leq \frac{18 - 15}{1.25}) - P(z\leq \frac{14 - 15}{1.25})

=P(z\leq \frac{3}{1.25}) - P(z\leq -\frac{1}{1.25})

=P(z\leq 2.4) - P(z\leq -0.8)

= 0.9918 - 0.2119

= 0.7799

8 0
3 years ago
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