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11111nata11111 [884]
2 years ago
7

The area of the shaded region is 20 cm. Find the value of x

Mathematics
1 answer:
dolphi86 [110]2 years ago
3 0
If you could put more info ab this then i would understand what u want me to put
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The cost of a car rental is twenty-five dollars a day plus ten cents a mile. What is the total cost, in dollars, if the car is r
Fudgin [204]

Answer:

The total cost is D) $141

Step-by-step explanation:

To solve we can use the equation: y=25d+0.10m

d= number of days  m= number of miles

We know both of these values so we can plug them in and solve.

y= 25(3) + 0.10(660)

y= 75 + 66

y = 141

4 0
3 years ago
How is -16/20 and 20/-25 represent the same rational number
sammy [17]

Answer:

-.8

Step-by-step explanation:

ok so if you divide -16 by 20 you will get -0.8

and if you divide 20 by -25 your answer also be -0.8

they are equal

4 0
3 years ago
How many solutions does the system of equations have?
sertanlavr [38]
Y = 4 x + 3 
<span>y = 4 x + 3/2 
</span>no solution :) hope this helps
7 0
3 years ago
Read 2 more answers
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
Can I get some help we just started this today?
soldier1979 [14.2K]

Answer:

Y=3x + 4

Step-by-step explanation:

Gradient = rise/run

=9/3

=3

Y-intercept is also 4

4 0
2 years ago
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