Answer:
I need the expressions
Step-by-step explanation:
(I don't have the experresions but I think it might be helpful to simplify)
- f - 5 ( 2 f - 3)
−f−10f+15
−f−(10f−15)
(−f−10f)+15
<u>−11f+15
</u>
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<u>Hope this helped</u>
4,646,536 is the right answer
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
solution is (x, y ) → (- 1, 4 )
y + 2x = 2 → (1)
y + 4x = 0 → (2)
subtract equation (1) from (2) to eliminate term in y
(y - y ) + (4x - 2x ) = (0 - 2 )
2x = - 2 ( divide both sides by 2 )
x = - 1
substitute x = - 1 in either (1) or (2) and solve for y
(1) → y - 2 = 2 ( add 2 to both sides )
y = 4
solution is (x, y ) → (- 1, 4 )
Answer:
20
Step-by-step explanation:
you first multiply 7 and three
then add that to four
then subtract 5
