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2 years ago

What are the answers to these simplified

Mathematics

2 answers:

Contact [7]2 years ago

6 0

Answer:

First of all you have to know that,

( + ) × ( + ) = ( + )

( - ) × ( - ) = ( + )

( + ) × ( - ) = ( - )

Now let us solve now.

- ( 5x + 3y + 5z ) + 6x

- 5x - 3y - 5z + 6x

- 5x + 6x - 3y - 5z

x - 3y - 5z

- ( 4x - 5y + 8 )

- 4x +5y - 8

6t - ( 5r - 4p + 9 )

6t - 5r + 4p -9

-2 ( 3x + 7y )

- 6x - 14y

Hope this helps you :-)

Let me know if you have any other questions :-)

DiKsa [7]2 years ago

5 0

Answer = refer to the pictures

hope this helps :)

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Out of seniors at a local high school, 60% went on the senior trip. At the hotel , one room was reserved for every 4 students .

sweet [91]

Answer:

<u>Number of rooms reserved for the students are - 90 .</u>

Step-by-step explanation:

Firstly ,

As we know 60% of the 600 students went on the trip,

Then ,

Number of students went on the trip = 60% of 600

= $\frac{60}{100}\times600$

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Now ,

Given - One room is reserved for 4 students ,

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<u>Hence , the answer is 90 rooms reserved for the students.</u>

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What is the slope intercept of the line (-9,7) (9,1)

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3 years ago

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3 years ago

The heights of young women aged 20 to 29 follow approximately the N(64, 2.7) distribution. Young men the same age have heights d

murzikaleks [220]

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Step-by-step explanation:

Let minimum height of the tallest 25% of young women be M.

Let Q be the random variable which denotes the height of young women.

Therefore, Q – N(64,2.70)

Now, P(Q˂M) = 1-0.25

i.e. P[(Q-64)/2.7 ˂ (M-64)/2.7] = 0.75

I.e. ф-1 [(M-64)/2.7] = 0.75 i.e. (M-64)/2.7 = ф-1 (0.75) = 0.675 i.e. M = 65.8198 inches

Let R be the random variable denoting the height of young men

Therefore, R – N (69.3, 2.8)

i.e. (R-69.3)/2.8 – N(0,1)

therefore the probability required = P(R ˂65.8198) = P[(R-69.3)/2.8 ˂ (65.8198 – 69.3)/2.8]

this gives P[(R-69.3)/2.8 ˂] = ф (-1.2429) = 0.107033

From this, the percentage of young men shorter than the shortest amongst the tallest 25% of young women is 10.703%

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