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1 year ago

In Exercises 1 and 2, identify the bisector of ST. Then find ST.

Mathematics

1 answer:

Lemur [1.5K]1 year ago

3 0

Given:

A bisector is a line or point that divides a line in half. So point M is in the middle of the entire line ST.

The bisector would be the line MW

This means line MT is half of the enitre line ST so then the entire line is 19*2.

Answer:

ST = 38

Bisector is line MW

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Using the slope and the y-intercept, graph the line represented by the following equation. Then select the correct graph. 3y = 2

Over [174]

First, let's write the given equation in slope-intercept form: y = mx + b

In slope-intercept form, the slope of the line is m, and the y-intercept is b. The slope is a measure of how steep the graph is at any point and is found by doing rise over run. This means the change in y values divided by the change in x values. Next, y-intercept is just where the graph crosses the y axis.

All we need to do to get the equation in slope-intercept form is to divide each term by 3. This will isolate the y.

$y= \frac{2}{3}x-2$

As you can see, the slope of the line is 2/3, and the y-intercept is -2.

To graph the line, plot a point at (0,-2). This is the point where the graph crosses the y axis. Then from that point, count up two and right 3. Plot a point here as well. Lastly, connect the two points with a straight line.

See attached picture for the graph.

5 0

3 years ago

Read 2 more answers

-7,-12,-17,-22,-27 find the nth term

Bess [88]

Answer:

-2 - 5n

Step-by-step explanation:

-7, -12, -17, -22, -27.....

Arithmetic Sequence

first term a = -7

difference = d = -12 - (-7) = -12 + 7 = (-5)

nth term = a + (n-1)d

= -7 + (n-1)*(-5)

= -7 + (-5)*n -1 * (-5)

= -7 - 5n + 5

= -2 - 5n

6 0

3 years ago

Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract

anyanavicka [17]

Answer:

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8$

Step-by-step explanation:

The sum you are trying to understand is this.

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}$

Remember that in general when you have a geometric series

$\sum\limits_{n = 0}^{\infty} a*r^n$ you have that

$\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}$ and that equality is true as long as $|r| < 1$ .

Therefore here we have

$\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n$ and $\big|\frac{-1}{15} \big| = \frac{1}{15} < 1$