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Rom4ik [11]
2 years ago
7

How many times greater is 9 x 10^12 than 3 x 10^6

Mathematics
1 answer:
Harrizon [31]2 years ago
7 0
<h3>Answer:   3 x 10^6</h3>

This is the number 3,000,000 aka 3 million

=======================================================

To find this answer, we divide the two values (large/small)

(9 x 10^12)/(3 x 10^6)

(9/3) x 10^(12-6)

3 x 10^6

We divided the stuff out front like normal (9/3 turns into 3) and we subtract the exponents when dividing the 10^12 over 10^6. The general rule is that

(a^b)/(a^c) = a^(b-c)

The result 3 x 10^6 is in scientific notation. It represents the number 3,000,000 aka 3 million. While 9 x 10^12 represents 9,000,000,000,000 which is the number 9 trillion.

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Mathematics Financial literacy
hichkok12 [17]

Answer:

$10,500

Step-by-step explanation:

since his income is b/n $50,000 and $100,000, he pays 15%, (15/100)70,000=$10,500

7 0
3 years ago
A triangle's side lengths are 15 cm and 10 cm. Write an inequality to determinte the possible measure for the missing side lengt
Klio2033 [76]

Answer:

the missing side lenght = x

0 < x < 15+10

0 < x < 25 cm

7 0
2 years ago
There is a store where people enter at a rate of 3 for each day. what is the probability that this store will have at least two
OverLord2011 [107]
If 3 people are going to the store each day
the probablity is 100%
8 0
3 years ago
LMNP is a rectangle. Find the value of x and the length of each diagonal LN= 4x + 13 and MP=9x - 7​
Volgvan

Answer:

5/3

Step-by-step explanation:

Since the given figure is a rectangle with congruent diagonals and thus equal lengths, you can use the expressions for the diagonal lengths, set them equal, and solve the equation for x.

7 0
2 years ago
Construct the discrete probability distribution for the random variable described. Express the probabilities as simplified fract
lisov135 [29]

Answer:

P(X = 0) = 0.03125

P(X = 1) = 0.15625

P(X = 2) = 0.3125

P(X = 3) = 0.3125

P(X = 4) = 0.15625

P(X = 5) = 0.03125

Step-by-step explanation:

For each toss, there are only two possible outcomes. Either it is tails, or it is not. The probability of a toss resulting in tails is independent of any other toss, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Fair coin:

Equally as likely to be heads or tails, so p = 0.5

5 tosses:

This means that n = 5

Probability distribution:

Probability of each outcome, so:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.5)^{0}.(0.5)^{5} = 0.03125

P(X = 1) = C_{5,1}.(0.5)^{1}.(0.5)^{4} = 0.15625

P(X = 2) = C_{5,2}.(0.5)^{2}.(0.5)^{3} = 0.3125

P(X = 3) = C_{5,3}.(0.5)^{3}.(0.5)^{2} = 0.3125

P(X = 4) = C_{5,4}.(0.5)^{4}.(0.5)^{1} = 0.15625

P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125

5 0
2 years ago
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