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Sveta_85 [38]
2 years ago
13

Solution for y=1/3x+2 and x=9

Mathematics
1 answer:
Kaylis [27]2 years ago
6 0

Hi!

To do this, we plug 9 in for x, and then solve.

y = 1/3<em>(9)</em> + 2

<em />

<em>multiply 1/3 and 9</em>

y = 3 + 2

<em />

<em>add 3 and 2</em>

y = 5

Hope this helps! :D

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Make x the subject of the formula y= 2x +5
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Answer:

x= (y-5)/2

Step-by-step explanation:

Isolate the x variable.

y= 2x +5

Subtract 5 from both sides.

y-5=2x

Divide both sides by 2.

(y-5)/2= x

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a.

The polynomial w^2+18w+84 cannot be factored

The perfect square trinomial is w^2+18w + 81

----------

The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.

w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9

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b.

The polynomial y^2-10y+23 cannot be factored

The perfect square trinomial is y^2-10y + 25

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Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.

If we want to complete the square for y^2-10y, we take half of the -10 to get -5, then square this to get 25. Therefore, y^2-10y+25 is a perfect square and it factors to (y-5)^2 or (y-5)(y-5)

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A researcher wishes to be 95% confident that her estimate of the true proportion of individuals who travel overseas is within 3%
andre [41]

Answer:  a) 683   b) 1067

Step-by-step explanation:

The confidence interval for population proportion is given by :-

p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

a) Given : Significance level :\alpha=1-0.95=0.05

Critical value : z_{\alpha/2}}=\pm1.96

Margin of error : E=0.03

Formula to calculate the sample size needed for interval estimate of population proportion :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.2(0.8)(\dfrac{1.96}{0.03})^2=682.951111111\approx683

Hence, the required sample size would be 683 .

b) If no estimate of the sample proportion is available then the formula to calculate sample size will be :-

n=0.25(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.03})^2=1067.11111111\approx1067

Hence, the required sample size would be 1067 .

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