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Evgesh-ka [11]
2 years ago
12

Can someone help me with these please?

Mathematics
1 answer:
zalisa [80]2 years ago
8 0

Answer:

9. g= 1, -10

10. r = 0.5, 1

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Can someone help me?<br><br> Brainlest for anyone who helps and explains<br><br> Thank you!!
Xelga [282]
The answer would be 10. Explanation: So basically you add the two complementary angles and set it equal to the whole thing. So it would look like 4x+46=7x+16. Then, you have to solve for x. To do that, subtract the 4x from both sides and the 16 from both sides. That will leave you with 3x=30. Then, divide by 3, and you get an answer of 10. Hope that helped :)
6 0
3 years ago
Please help thanks :)
kykrilka [37]
Question 1:

Multiply both sides of the proportion by 35.

You get.

7(x-1) = 4x+2

7x-7 = 4x+2

Now, add both sides by 7 and subtract both sides by 4x

3x = 9

Divide both sides by 3

x=3

Question 2:

Multiply both the numerator and the denominator of \frac{x+1}{x+3} by 3.

We want to multiply it by 3 so that the +1 and +3 become +3 and +9. +3 and +9 have a difference of 6, just like 15 and 21, which is what we want.

\frac{3x+3}{3x+9} = \frac{15}{21}

Set the numerator equal to the numerator and the denominator equal to the denominator.

3x+3 = 15

3x+9 = 21

If you solve both of these, you get x=4 for both.

That's your answer.

Hope this helps! :)
8 0
3 years ago
Use the diagram to answer the following questions.125°Lx2X+10NmZNPMdegreesmZLPMdegrees
lutik1710 [3]

For the angle MPN we know that is oposite to the angle QPL so the will be equal so:

\angle MPN=125º

Now with the value of MPN we can made an equation for x so:

125=2x+10

and we solve for x

\begin{gathered} 125-10=2x \\ \frac{115}{2}=x \\ 57.5=x \end{gathered}

and the angle LPM will be the complementari angle of 125 so:

\begin{gathered} \angle LPM=180-125 \\ \angle LPM=55º \end{gathered}

4 0
1 year ago
If the half-life of a radioactive substance is 2,800 years, then at what rate is it decaying?
vlada-n [284]

Answer:

0.0001075

Step-by-step explanation:

The relation between halflife and rate at which it is decaying is given by

t_{\frac{1}{2} } =\dfrac{log2}{rate}

now in the above problem halflife is given as 2800 years substituting in the above equation we get the value of rate at which it is decaying to be rate=0.0001075.

6 0
3 years ago
I need help ASAP I'll vote brainleist
babunello [35]

Answer:

blue 1

yellow 2

black 1/5

Step-by-step explanation:

blue 1

yellow 2

black 1/5

8 0
3 years ago
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