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icang [17]
2 years ago
9

Ansh has a 9m 4 cm rope with him. He cut it into two parts .If the length of one part is 6 m 80 cm , what is the length of other

part ?​
Mathematics
2 answers:
Step2247 [10]2 years ago
6 0
Length of other part = length of the rope- length of the first part
= 9m 4cm -6 m 80cm
= 8m 104 cm - 6 m 80 cm
= 2 m 24 cm
aivan3 [116]2 years ago
5 0

Answer:

2m 24cm

Step-by-step explanation:

Since we're dealing with two units of measurement, we will have to subtract both units individually.

9 - 6 = 3m

4 - 80 = -76.

Also note that in one m, there is 100 cm.

So, we are going to take one 100 and subtract it by 76.

100 - 76 = 24.

Therefore, the length of the other part is 2m 24cm

<em>-kiniwih426</em>

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<u>using these information</u>:

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3 years ago
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Answer:

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Answer:

jupiters \: mass \: is \: approximatelty \:  \\   \boxed{{6 \times 10}^{3} \: kg}  \: times, \:  \\ more \: than \: mercurys \: mass

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............................................................... \\ in \: other \: to \: get \: right \: ans \to \\ you \: divide \: mass \: of \: jupiter \: by \: the \: mass \\  \: of \: mercury : \: so \to \\ ............................................................... \\ jupiters \: mass = 1.898 { \times 10}^{27}  \: kg \\ mercurys \: mass =3.3 \times  {10}^{23}   \: kg \\ their \: mass \: ratio \: is :  \\  =  \frac{1.898 { \times 10}^{27}}{3.3 \times  {10}^{23}}  = 0.5751515152 \times  {10}^{4}   =  \\  \boxed{5,751.515152} \\ hence \: jupiters \: mass \: is \: approximatelty \:  \\  {6 \times 10}^{3}  \: times \: more \: than \: mercurys \: mass

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