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torisob [31]
3 years ago
7

Use the table. What is the total amount o

Mathematics
2 answers:
irina1246 [14]3 years ago
8 0

Answer:

1.89

Step-by-step explanation:

0.09+1.5+0.3

anygoal [31]3 years ago
7 0
1.89 Because you have to add the numbers
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66) A farmhouse shelters 13 animals. Some are cows and some are chickens. Altogether there are 38
yuradex [85]

Answer:

9 cows and 1 chicken ( plz help me)

Step-by-step explanation:

6 0
3 years ago
In this problem,y = 1/(x2 + c)is a one-parameter family of solutions of the first-order DEy' + 2xy2 = 0.Find a solution of the f
trasher [3.6K]

Differentiate the given solution:

y=\dfrac1{x^2+C}\implies y'=-\dfrac{2x}{(x^2+C)^2}

Substitute y and y' into the ODE:

-\dfrac{2x}{(x^2+C)^2}+2x\left(\dfrac1{x^2+C}\right)^2=0

and it's easy to see the left side indeed reduces to 0.

6 0
3 years ago
What is the area of this figure?
umka21 [38]
137.5 I took the test and got 100% 


3 0
3 years ago
Read 2 more answers
The houck family's train traveled 552 miles in 6 hours. The Roberts family traveled at 744 miles in 8 hours which family is trav
rusak2 [61]

Answer: Both families were travelling at the same speed/rate of 1mile/0.65mins or 1mile/0.01hr.

Step-by-step explanation: Speed of Houck family's train = 552m/6hrs

speed of Robert family's train = 744m/8hrs.

Therefore considering Houck speed,

552miles = 6hours

1mile = (6 x 60)/552

= 360/552

= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr

For Robert

744miles = 8hours

1mile = ( 8 x 60 )/744

= (480/744)minutes

= 0.645

= 0.65minutes. Average speed = 1mile/0.65mins. Or 1mile/0.01hr

Conclusion: Both families were travelling at the same speed/rate.

To get that minutes in hour, just divide by 60 to get concert to hours.

6 0
4 years ago
A Geometric series has a first term of 4 and a common ratio of 6. what formula is equivalent to the partial sum of the first n t
IRISSAK [1]
\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=6
\end{cases}
\\\\\\
S_n=4\left( \cfrac{1-6^n}{1-6} \right)\implies S_n=4\left( \cfrac{1-6^n}{-5} \right)
6 0
3 years ago
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