The answer is 
Logarithm both sides of the equation:
Since:
, then: 
Back to our equation:
Logarithm both sides of the equation:
Since:
Back to our equation:
PLEASE HELP WILL GIVE BRIANLIEST!!!
1 answer:
You might be interested in
Answer:
f'(N) = a(k² - N²)/(k² + N²)
The function increases in the interval
(-k < N < k)
And the function decreases everywhere else; the intervals given as
(-∞ < N < -k) and (k < N < ∞)
Step-by-step explanation:
f(N)=aN/(k²+N²)
The derivative of this function is obrained using the quotient rule.
Then to determine the intervals where the function is increasinumber and decreasing,
The function increases in intervals where f'(N) > 0
and the function decreases in intervals where f'(N) < 0.
This inequality is evaluated and the solution obtained.
The solution is presented in the attached image.
Hope this Helps!!!
