The number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600
<h3>How to determine the number of passwords</h3>
The given parameters are:
Password length = 8
Letters = 6
Numbers = 2
There are 26 letters and 10 digits.
Since the letters and the numbers can be repeated, then the number of passwords is:
Count = 26^6 * 10^2
Evaluate
Count = 30891577600
Hence, the number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600
Read more about combination at:
brainly.com/question/11732255
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<u>Answer:</u>
Below!
<u>Step-by-step explanation:</u>
<u>The best way to answer this question is to read the statement carefully.</u>
- => Five less than twice a number = 2x - 5
- => Five times the sum of two numbers = 5(x + y)
- => The difference of 5 and a number, squared = (5 - x)²
Hoped this helped.
Answer:
the answer is the first one
Step-by-step explanation:
perp to x-3y=2 thru (2,4)
For perpendicular we swap the coefficients on x and y, negating one
3x + y = some constant
We get the constant in the obvious way from the point
3x + y = 3(2) + 4 = 6 + 4 = 10
Answer: 3x + y = 10
Answer:
Step-by-step explanation:
Angle A is given.
For angle A, BC is the opposite leg.
For angle A, AC is the adjacent leg.
The trig ratio that relates the opposite leg to the adjacent leg is the tangent.
In general, for angle X,
In our problem,
