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3 years ago

Which equation is best represented by the graph below?

2 answers:

8 0

Answer:

y=14x-2y is equal to 1 fourth x minus 2

Explanation: use rise over run use each answer to see which fits the graph.

Blababa [14]3 years ago

6 0

Hi, i would love to help you but there is no graph below :(

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Find the volume of a rectangular prism that has a height of 5 meters and the area of the base is 8cm squared

Wewaii [24]

Answer:

Volume of prism = 4000 cm cubed

Step-by-step explanation:

Given that:

Height of rectangular prism = 5 meters

Converting into centimeters as the area of base is in centimeters.

1 meter = 100 centimeter

5 meters = 500 cm

Area of the base = 8 cm squared

Volume of prism = Area of base * Height

Volume of prism = 8 * 500

Volume of prism = 4000 cm cubed

Hence,

Volume of prism = 4000 cm cubed

7 0

3 years ago

8 hundreds +2 hundreds unit form

goldenfox [79]

The answer would be 1000 or 10 hundreds

5 0

3 years ago

1. Using the factorisation method, simplify the following √32

dezoksy [38]

Answer:

$4 \sqrt{2}$

$\sqrt{32} = \sqrt{16 \times 2} = 4 \sqrt{2}$

6 0

3 years ago

What is the product?

Soloha48 [4]

Answer is

<span>B. 1/3a

hope it helps</span>

8 0

3 years ago

Read 2 more answers

Lines p, q, and r all pass through point (-3,4). Line p has slope 4 and is perpendicular to line q. Line r passes through Quadra

Sergio [31]

Answer:

Part 1) The equation of line p is $y=4x+16$

Part 2) The equation of line q is $y=-\frac{1}{4}x+\frac{13}{4}$

Part 3) The equation of line r is $y=4$

The graph in the attached figure

Step-by-step explanation:

step 1

Find the equation of the line p

we have

$m=4\\point\ (-3,4)$

Find the equation in point slope form

$y-y1=m(x-x1)$

substitute

$y-4=4(x+3)$ ----> equation in point slope form

Convert to slope intercept form

$y-4=4x+12$

$y=4x+12+4$

$y=4x+16$

step 2

Find the equation of line q

we know that

If two lines are perpendicular, then their slope are opposite reciprocal (the product of their slopes is equal to -1)

we have that

Line q is perpendicular to line q

$m_q*m_p=-1$

we have

$m_p=4$

therefore

$m_q=-\frac{1}{4}$

we have

$m=-\frac{1}{4}\\point\ (-3,4)$

Find the equation in point slope form

$y-y1=m(x-x1)$

substitute

$y-4=-\frac{1}{4}(x+3)$ ----> equation in point slope form

Convert to slope intercept form

$y-4=-\frac{1}{4}x-\frac{3}{4}$

$y=-\frac{1}{4}x-\frac{3}{4}+4$

$y=-\frac{1}{4}x+\frac{13}{4}$

step 3

Find the equation of line r

we know that

Line r passes through Quadrants 1 and Quadrants 2 only and passes through the point (-3,4)

therefore

The equation of Line r must be equal to the y-coordinate of the given point

$y=4$ ----> is a horizontal line

step 4

Graph the three lines

using a graphing tool

see the attached figure

4 0

3 years ago