All categories

3 years ago

Which equation is best represented by the graph below?

2 answers:

8 0

Answer:

y=14x-2y is equal to 1 fourth x minus 2

Explanation: use rise over run use each answer to see which fits the graph.

Blababa [14]3 years ago

6 0

Hi, i would love to help you but there is no graph below :(

You might be interested in

What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti

Marat540 [252]

Answer:

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

Step-by-step explanation:

Given

$x^2 - 5x - 7 = 0$

Required

Solve for x using:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

First, we need to identify a, b and c

The general form of a quadratic equation is:

$ax^2 + bx + c = 0$

So, by comparison with $x^2 - 5x - 7 = 0$

$a = 1$ $b = -5$ $c = -7$

Substitute these values of a, b and c in

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}$

$x = \frac{5 \± \sqrt{25 +28}}{2}$

$x = \frac{5 \± \sqrt{53}}{2}$

Split the expression to two

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

To solve further in decimal form, we have

$x = \frac{5 + 7.28}{2}$ or $x = \frac{5 - 7.28}{2}$

$x = \frac{12.28}{2}$ or $x = \frac{-2.28}{2}$

$x = 6.14$ or $x = -1.14$

4 0

3 years ago

Find the condition that one root of the quadratic equation may be 1 more than the other.

Eddi Din [679]

<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>

4 0

4 years ago

What are the factor pairs for 10?

sineoko [7]

The pairs are 1 and 10. 2 and 5.

3 0

3 years ago

Defina qué es el producto de un vector por un escalar

Ostrovityanka [42]

Answer: c

Step-by-step explanation:

5 0

3 years ago

If WXYZ is a square, which statements must be true? Check all that apply.

OLga [1]

Answer:

A might be right

hope this is helpful

8 0

2 years ago