The reaction that links monomers to make polymers is polymerization. This process is also referred to as dehydration synthesis. Two monomers are binding to each other and form one polymer. Example: hydrogen (H) from one monomer binds with a hydroxyl group (OH) from the other monomer and forms the polymer : H+<span> + OH</span>-<span> = H</span>2O - the <span>water molecule. </span>
Answer: Flexible springs
Explanation:
The atoms in an element or compound are bonded together by bonds which keeps the atoms together.
The bonds is stiff but it proves some flexibility for the movement of the atoms so that they can react and form different types of substances.
The bonds between the atoms act like flexible spring which keeps two or more atoms together and flexible for reacting.
That would be the mitochondria. They produce the energy needed for activities that occur in the cell, thus its being called the "powerhouse of the cell"
The correct order of the following events on the mass flow of materials in the phloem is:
- Leaf cells produce sugar by photosynthesis.
- Solutes are actively transported into sieve tubes.
- Water diffuses into the sieve tubes.
- Sugar moves down the stem.
Correct answer: letter C.
This is because the mass flow of materials in the phloem must pass through all these processes in a consecutive and orderly manner, from the cell to the stem, in order to allow nutrients and other vital materials to reach from the plant roots to the leaves and fruits.
<h3>How is this transport of nutrients and other vital materials achieved?</h3>
This is accomplished by the transport of solutes through the phloem's network of channels, which contain fluids, mineral salts, vitamins and other nutrients essential to plant health. Mass flow also helps distribute oxygen and carbon dioxide to all parts of the plant. These materials are necessary for plant respiration and growth.
Learn more about the phloem:
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Answer: The probability of obtaining an individual who is CcmmLLPp 1/32.
Explanation: This can be achieved by crossing similar genes to obtain individual probability as shown in the attached image.
When you cross Cc in the first genotype with CC in the second genotype, the following probabilities will be obtained;
P (CC) = ¾, P(Cc) = ¼.
Similarly, crossing Mm with mm, we get;
P (Mm) = ½, P (mm) = ½
Crossing Ll with Ll, we get
P (LL) = ¼, P (Ll) = ½, P (ll) = ¼
Crossing PP with pp, we get
P (Pp) = 1
Therefore, the probability of individual with genotype CcmmLLPp will be;
P (Cc) x P (mm) x P (LL) x P (Pp)
= ¼ x ½ x ¼ x 1
= 1/32
