Step One
Find the base area of the large hexagon as though the smaller one was not removed.
Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.
Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)
Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.
Area of the remaining piece = area of large hexagon - area of the small hexagon
Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)
Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18
I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3
Answer:
x = 10
Step-by-step explanation:
If you add the angles up, you get 110, so the missing angle is 70. It is an isosceles triangle. The bottom length should be about 11.
11 dollars all you have to do is take 550 and divide by 50 and you get 11 please give me brainlyeist
Answer:
3 x 8= 24
Step-by-step explanation:
Answer:
-1 1/8
Step-by-step explanation:
-3/4 / -8/12
= -3/4 * -12/8
= -3*12 / -4*8
= -36/32
= -1 4/32
= -1 1/8
