To solve this problem you must apply the proccedure shown below:
1. You have that the <span>parabola is 12 meters high at the vertex and at a height of 10 meters, the width is 8 meter.
2. Therefore, you have:
x^2=-4a(y^2-k)
4</span>^2=-4a(10-12)
16=-40a+48
16=8a
a=16/8
a=2
y=0
x^2=-8(0-12)
x^2=96
x=√96
x=9.79x2
x=19.58
3. Therefore, as you can see, the answer is: 19.58 meters.<span>
</span>
A.6x+34
B.8t+38
C.2y-14
D.11n+16
180 is the lcm for 20 and 18
V = L * W * H
V = 1/4 * 2/3 * 3/5
V = (1 * 2 * 3) / (4 * 3 * 5)
V = 6/60 reduces to 1/10 m^3 <==
Answer:
Point Form: (-4,5)
Equation Form: x=-4,y=5
Step-by-step explanation:
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