Answer: " m = zC / (C − z) " .
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Explanation:
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Given: 1/C + 1/m = 1/z ; Solve for "m".
Subtract "1/C" from each side of the equation:
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1/C + 1/m − 1/C = 1/z − 1/C ;
to get: 1/m = 1/z − 1/C ;
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Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;
to get: zC = mC − mz ;
Factor out an "m" on the "right-hand side" of the equation:
zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;
zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24
zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
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Answer:
B and D
Step-by-step explanation:
B:
Anything to a negative power means that it is 1/that to the positive power.
E.g. x^-1 = 1/x^1
In other words, anything to the power of a negative switches sides of a fraction (i.e. if in numerator moves to denominator and vice versa.)
1/x^-1 = 1/1/x^1 which is just equal to x, because there are x number of 1/xs in one (1/x * x =1) Therefore Option B is equal to just x.
D: (assuming the first given term is x^1/3 and not X1/3 (?) Correct me if I'm wrong).
x^1/3 * x^1/3 * x^1/3 is also equal to just x.
This is because when multiplying together terms with the same base (x in this case) the exponents just add together, so:
x^1/3 * x^1/3 * x^1/3 = x^(1/3 +1/3 +1/3) = x^1 = x.
Therefore B and D are equivalent because they both equal x.
Hope this helped!
Answer: 1/6 is not equal to 6/12 because 6/12 is 1/2 and 1/6 is less
Step-by-step explanation:
There are various ways in which to do this problem. I'd suggest
converting 5 3/4 into an improper fraction and then dividing that improper fraction by 4:
20+3 23 1 23
------- divided by 4 is --------- * ----- = ------ (answer)
4 4 4 16
