Answer:\ b.
Step-by-step explanation:
Hope this helps!!
Answer:
6214
Step-by-step explanation:
you round up 62 and 4 20 times and that is your answer but for give me if this answer wrong
Answer:
{x,y} = {-2,-3}
Step-by-step explanation:
System of Linear Equations entered :
[1] -9x + 4y = 6
[2] 9x + 5y = -33
Graphic Representation of the Equations :
4y - 9x = 6 5y + 9x = -33
Solve by Substitution :
// Solve equation [2] for the variable y
[2] 5y = -9x - 33
[2] y = -9x/5 - 33/5
// Plug this in for variable y in equation [1]
[1] -9x + 4•(-9x/5-33/5) = 6
[1] -81x/5 = 162/5
[1] -81x = 162
// Solve equation [1] for the variable x
[1] 81x = - 162
[1] x = - 2
// By now we know this much :
x = -2
y = -9x/5-33/5
// Use the x value to solve for y
y = -(9/5)(-2)-33/5 = -3
I believe it is zero, because there is no number less than 1.
Since ![[0,4]=[0,1]\cup(1,4]](https://tex.z-dn.net/?f=%5B0%2C4%5D%3D%5B0%2C1%5D%5Ccup%281%2C4%5D)
, we can rewrite the integral as
Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:
Both integrals are quite immediate: you only need to use the power rule
to get
![\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_0%5E11-3t%5E2%5C%3Bdt%20%3D%20%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%2C%5Cquad%20%5Cint_1%5E4%202t%5C%3B%20dt%20%3D%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4)
Now we only need to evaluate the antiderivatives:
![\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15](https://tex.z-dn.net/?f=%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%20%3D%201-1%5E3%3D0%2C%5Cquad%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4%20%3D%204%5E2-1%5E2%3D15)
So, the final answer is 15.
