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Setler [38]
3 years ago
8

For each value of U, determine whether it is a solution,

Mathematics
1 answer:
abruzzese [7]3 years ago
8 0
Given u/7 - 1 = 7 and plugging in values for u,

For u = 28; 28/7 - 1 = 4 - 1 = 3; No
For u = -49; -49/7 - 1 = -7 - 1 = -8; No
For u = 42; 42/7 - 1 = 6 - 1 = 5; No
For u = 0; 0/7 - 1 = -1; No

Another way to find out which value would be a solution to u/7 - 1 = 7 is to solve for u.

u/7 - 1 = 7
u/7 = 7 + 1
u/7 = 8
u = 8*7
u = 56

The only solution to this equation is when u = 56.
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Zack uses fruits and nuts to make a trail mix . He uses 2 cups of fruit every 3 cups of nuts
dolphi86 [110]

Answer:

So he makes 5 cups of trail mix.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is a reflection of point R(-2,9) first across the y-axis and then across the x-axis?
docker41 [41]
I would say C because it is the only one that makes the most sense, if you reflect something from the y-axis, the negatives become positives, and the positives become negitives
5 0
3 years ago
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Two friends are going to the mall to buy pizza. One of the friends buys 1cheese slice and 2 pepperoni slices for $8.75. Her frie
GarryVolchara [31]

Answer:

The cost of each:

1 cheese slice = c = $3.75

1 pepperoni slice = p = $2.5

Step-by-step explanation:

Let the cost:

1 cheese slice = c

1 pepperoni slice = p

Two friends are going to the mall to buy pizza.

One of the friends buys 1cheese slice and 2 pepperoni slices for $8.75.

c + 2p = $8.75.....Equation 1

c = $8.75 - 2p

Her friend purchases 2 chese slices and 3 pepperoni slices for $15.00.

2c + 3p = $15.00.....Equation 2

We substitute 8.75 - 2p for c in Equation 2

2(8.75 - 2p) + 3p = $15.00

17.5 - 4p + 3p = 15

Collect like terms

- 4p + 3p = 15 - 17.5

-p = -2.5

p = $2.5

c = $8.75 - 2p

c = $8.75 - 2(2.5)

c = $8.75 - 5.0

c = $3.75

The cost of each:

1 cheese slice = c = $3.75

1 pepperoni slice = p = $2.5

6 0
3 years ago
How do you find the normal approximation without using the continuity correction?
Dennis_Churaev [7]
Let's say you want to compute the probability \mathbb P(a\le X\le b) where X converges in distribution to Y, and Y follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing Y such that its mean and variance are the same as those for X.

Example: If X is binomially distributed with n=100 and p=0.1, then X has mean np=10 and variance np(1-p)=9. So you can approximate a probability in terms of X with a probability in terms of Y:

\mathbb P(a\le X\le b)\approx\mathbb P(a\le Y\le b)=\mathbb P\left(\dfrac{a-10}3\le\dfrac{Y-10}3\le\dfrac{b-10}3\right)=\mathbb P(a^*\le Z\le b^*)

where Z follows the standard normal distribution.
8 0
3 years ago
Complete the remainder of the<br> table for the given function rule:
melamori03 [73]

Answer:

-3=2

0=0

3=-2

6=-4

3 0
2 years ago
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