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NemiM [27]
2 years ago
14

Write an equation of the line passing through the point(2,10)

Mathematics
1 answer:
Arlecino [84]2 years ago
7 0
Rearrange 2x+y=17 to slope intercept form: y=-2x+17
slope of that equation is -2 and perpendicular slope is 1/2
use point slope form and put the point(2,10) and slope in there to get y-10= 1/2(x-2)
rearrange to get y=1/5x+9.6
This should be correct
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Find the area of the trapezoid to the nearest tenth.
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Answer:

2.2 metres squared

Step-by-step explanation:

We need to find the area of this trapezoid.

The area of a trapezoid is denoted by:

A=\frac{(b_1+b_2)h}{2}, where b_1 and b_2 are the parallel bases and h is the height

Here, we already know the lengths of the two bases; they are 0.9 metres and 2.3 metres. However, we need to find the length of the height.

Notice that one of the angles is marked 45 degrees. Let's draw a perpendicular line from top endpoint of the segment labelled 0.9 to the side labelled 2.3. We now have a 45-45-90 triangle with hypotenuse 2.0 metres. As one of such a triangle's properties, we can divide 2.0 by √2 to get the length of both legs:

2.0 ÷ √2 = √2 ≈ 1.414 ≈ 1.4

Thus, the height is h = 1.4 metres. Now plug all these values we know into the equation to find the area:

A=\frac{(b_1+b_2)h}{2}

A=\frac{(0.9+2.3)*1.4}{2}=2.2

The answer is thus 2.2 metres squared.

<em>~ an aesthetics lover</em>

8 0
3 years ago
SOLVE x^4 − 15x^2 − 16 = 0 <br> What are the roots of the equation?
kakasveta [241]

Answer:

roots : 4, -4, i, -i

Step-by-step explanation:

This gets a bit tricky.

We have to substitude x^2 as u in this problem.

Now to rewrite x^4 − 15x^2 − 16 = 0 with u, we get

u^2 - 15u - 16 = 0

( u - 16) (u + 1)

U = 16

U = -1

<em>This is not the end of the problem. </em>

Now we have to substitute x^2 back to u.

x^2 = 16  --> we get the roots 4 and -4

x^2 = -1 --> we get the roots i and -i

tadah!

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Answer:

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Step-by-step explanation:

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3 years ago
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patriot [66]

Answer:

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Step-by-step explanation:

Hope it helps you

5 0
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What is the equation of the line that passes through the point (6,-5) and has a
lora16 [44]
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hope this helps!!
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