5 desert animals are camel, sand cat, desert tortoises, desert lizards and the great road runner.
<u>Explanation:</u>
- Camel has several physiological and behavioral adaptations that help them survive the extreme conditions of the desert. They have flat feet to help them spread their weight in the sand.
- They have thick eyelashes and closeable nostrils to prevent the entry of sand. They store fat on their humps that supplies energy during long journeys and has a long large intestine which increases water reabsorption.
- Sand cat is similar to the domestic cat in basic appearance but has several adaptations enabling it to survive in the desert. Their paws are covered with thick and long hairs to protect the feet from the heat. They have thick fur that acts as an insulting surface during hot days and cold nights.
- Desert tortoises have excellent water storage capacity. Their bladders are larger than normal and can carry extra water. They have strong feet which helps them to dig holes in the sand and access rainwater.
- Desert lizards can drink water through skin. They do it by a process called cutaneous water acquisition and it helps them to gather water obtained from rainfall, damp sand and pools.
- Great roadrunner has peculiar adaptations. The digestive system of the bird retrieves water from the feces as it is in the excretory canal.
Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.
Answer:
It is B, Chloroplasts use carbon dioxide and water to create glucose.
Explanation:
I just had this question and got it right somehow, so there is the answer that was right for me.
Hii...so the answer is
The four layers are the external oblique, internal oblique, transverse abdominals.
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Answer:
A. Redshift and Blueshift
Explanation:
It’s red shift and blue shift, because this only occurs when the frequency of the wave is made longer or shorter due to the movement of the source relative to the observer.
