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Natali [406]
2 years ago
7

Name a number that has the same absolute value as 23

Mathematics
2 answers:
Ede4ka [16]2 years ago
8 0

Answer:

-23

Step-by-step explanation:

same distance from zero.

IRINA_888 [86]2 years ago
6 0

Answer: A number with the same absolute value of 23 is -23.

Explanation: The absolute value of a number is how far it is from zero, and the absolute value of a number is always positive, unless the number is 0, in which case the absolute value is neutral, and the absolute value is 0.

Examples: 6 is 6 away from zero, so the absolute value of 6 is 6.

−6 is 6 away from zero, so the absolute value of −6 is 6.

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There are 4grams of fiber in 1/2 cup of oats. how many grams of fiber are in 3 1/2 cuña of oats​
aleksklad [387]

Answer:

28 grams

Step-by-step explanation:

8 x 3 = 24

24 + 4 = 28

7 0
3 years ago
Divide 3 by 4, then subtract z from the result
8_murik_8 [283]

Answer:

3/4 = z

Step-by-step explanation:

<u>Step 1:  Convert words into an expression</u>

Divide 3 by 4, then subtract z from the result

3/4 - z

<u>Step 2:  Solve for z</u>

3/4 - z + z = 0 + z

3/4 = z

Answer:  3/4 = z

7 0
3 years ago
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HELP NOW! RIGHT ANSWER=BRAINLIEST<br> EXCUSE NAIL POLISH!!!!‍
Nutka1998 [239]

Answer:

60

Step-by-step explanation:

6% of 250 = 15 = 250 * 0.06

30% of 250 = 75 = 250 * 0.7

75-15=60

4 0
2 years ago
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Which equation represents a linear function?
Blababa [14]

Answer:

The third one, y=x-3

Step-by-step explanation:

A linear equation is any equation that can be written in the form. ax+b=0. Meaning it will not have a radical or be squared.

4 0
3 years ago
1. Find the Least Common Multiple of these two monomials:<br> See picture
gtnhenbr [62]

Answer:

<em>The last choice is correct</em>

<em />LCM=120a^4b^7c^5<em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

2^2,3,a^4,b^2,c^5

The prime factors of the second monomial are:

2^3,5,a^3b^7c^1

LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

Operating:

LCM=8*15*a^4*b^7*c^5

\boxed{LCM=120a^4b^7c^5}

The last choice is correct

3 0
4 years ago
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