Question

HELP PLZZZZZZZZZZZZZZZZZ :) brainliest to first answer

Answer 1

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Let's solve ~

$\qquad \leadsto\sf \: - 4y + b$

[ plug the values of y and b ]

$\qquad \leadsto\sf \: (- 4 \times \frac{3}{20} ) + \frac{9}{10}$

$\qquad \leadsto\sf \: - \frac{3}{5} + \frac{9}{10}$

$\qquad \leadsto\sf \: \frac{ - 6 + 9}{10}$

$\qquad \leadsto\sf \: \frac{3}{10}$

Answer 2

Answer:

3/10

Step-by-step explanation:

-4y +b

Let y = 3/20 and b = 9/10

-4 ( 3/20) + 9/10

-12/20 + 9/10

Simplify the first term

-6/10 + 9/10

3/10