Estimate then answer the equation.

Mathematics

1 answer:

devlian [24]3 years ago

6 0

Answer:

The estimation answer is about 6

The answer that is not estimated is 5 8/9

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2-33+(-4)+5-(-6)-70=

VikaD [51]

2-33+(-4)+5-(-6)-70=

2-33-4+5+6-70=
-35+5+6-70=
-30+6-70=
-24-70=
-94

Answer=-94

5 0

3 years ago

Helppp!!!!laura is playing a card game with her friend.she will draw two cards from those pictured.

puteri [66]

Answer:

30%

Step-by-step explanation:

In this case it would be the combination of 2 taken from 5.

That is, when n = 5 and r = 2

nCr = n! / r! * (n-r)!

replacing

5C2 = 5! / (2! * 3!)

5C2 = 10

Which means that the sample space is 10 possible combinations.

the probability that the card you draw is even is 3/5, since there are 3 even cards that exist and 5 is the total number of cards.

Now, so that both are for it would be the multiplication of the previous probability and 2/4 because an even card and a card in general have already been drawn:

(3/5) * (2/4) = 0.3

So the probability that both are even is 30%

5 0

3 years ago

WHAT IS X³-27 SIMPLIFIED

Eduardwww [97]

Answer:

It is (x - 3)³ - 9x(3 - x)

Step-by-step explanation:

Express 27 in terms of cubes, 27 = 3³:

$= {x}^{3} - {3}^{3}$

From trinomial expansion:

${(x - y)}^{3} = (x - y)(x - y)(x - y) \\$

open first two brackets to get a quadratic equation:

${(x - y)}^{3} = ( {x}^{2} - 2xy + {y}^{2} )(x - y)$

expand further:

${(x - y)}^{3} = {x}^{3} - y {x}^{2} - 2y {x}^{2} + 2x {y}^{2} + x {y}^{2} - {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3x {y}^{2} - 3y {x}^{2} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3xy(y - x) \\ \\ { \boxed{( {x}^{3} - {y}^{3} ) = {(x - y)}^{3} - 3xy(y - x)}}$