I have the answer in this picture. But im not sure if this might be really what your asking for.
Answer:
I think it is $1604.4
Step-by-step explanation:
I added 40% to 1146
You need to define h(x) to find its inverse.
The general answer is to replace h(x)= with y=. Then you make x the subject of the equation so that you get x= some function of y. That function is the inverse of the original function.
Example: h(x)=2x+5. Write y=2x+5. Now solve for x: x=(y-5)/2 so h⁻¹(y)=(y-5)/2 and h⁻¹(x)=(x-5)/2 is the inverse of h(x).
Hello,
Dividing by 0 is not defined so let s take x different from 4 and -4 and then we can write:
As
![f(x)=x^2-7x+12=x^2-4x-3x+12=x(x-4)-3(x-4)=(x-4)(x-3)\\ \\(f\times g)(x)=\dfrac{3(x-4)(x-3)}{(x-4)(x+4)}=\dfrac{3x-9}{x+4}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-7x%2B12%3Dx%5E2-4x-3x%2B12%3Dx%28x-4%29-3%28x-4%29%3D%28x-4%29%28x-3%29%5C%5C%20%5C%5C%28f%5Ctimes%20g%29%28x%29%3D%5Cdfrac%7B3%28x-4%29%28x-3%29%7D%7B%28x-4%29%28x%2B4%29%7D%3D%5Cdfrac%7B3x-9%7D%7Bx%2B4%7D)
Thanks
(arrange the data set from least to greatest)
0, 0, 2, 2, 3, 4, 6, 8
(find the median: *the middle number*)
Median: 2.5
Lower quartile: 1
Upper quartile: 5
Interquartile range : upper quartile - lower quartile = answer
Interquartile range: 5 - 1 = 4
So the IQR or interquartile for the following data set is 4.