Answer:
4x-3y+12=0 is required eqn
Step-by-step explanation:
Let, 3,8 be x1,y1
9,16 be x2,y2
Now,
Eqn of st.line is y-y1 = y2-y2/x2-x1 * (x-x1)
y-8 = 16-8/9-3 * (x-3)
y-8 = 4/3*(x-3)
3y-24 = 4x-12
4x-3y+12=0 is required eqn
Answer:
<u>Problem 4:</u> Option C, 32
<u>Problem 5:</u> You need to have the 2 and the x combine. Make the table 2x than 16.
<u>Problem 6:</u> x = 17
<u>Problem 7:</u> She drew a 2, x and an 16. Instead you must have 2x and 16. 2x + 16 = 50
Step-by-step explanation:
<u>Problem 4</u>
2 + x + 16 = 50
x + 18 - 18 = 50 - 18
x = 32
Answer: Option C, 32
<u>Problem 5</u>
You need to have the 2 and the x combine. Make the table 2x than 16.
Answer: You need to have the 2 and the x combine. Make the table 2x than 16.
<u>Problem 6</u>
2x + 16 - 16 = 50 - 16
2x / 2 = 34 / 2
x = 17
Answer: x = 17
<u>Problem 7</u>
She drew a 2, x and an 16. Instead you must have 2x and 16. 2x + 16 = 50
Answer: She drew a 2, x and an 16. Instead you must have 2x and 16. 2x + 16 = 50
c) y = 25^x
explanation
because y increase as x increases