Remember you can do anything to an equaiton as long asyou do it to both sides
4v+18≥6v+10
minus 4v both sides
4v-4v+18≥6v-4v+10
0+18≥2v+10
18≥2v+10
minus 10 both sides
18-10≥2v+10-10
8≥2v+0
8≥2v
divide both sides by 2
8/2=(2v)/2
4≥(2/2)v
4≥1v
4≥v
v≤4
Answer:
I would but...
Step-by-step explanation:
where the question at
Answer:
11 or 18 either one if im wrong sorry
Step-by-step explanation:
Answer:
![\sqrt{ {x}^{2} - 1 }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%7Bx%7D%5E%7B2%7D%20-%201%20%7D%20)
Solution,
base=1
perpendicular=?
hypotenuse=X
now,
using Pythagoras theorem,
x^2=p^2+b^2
or, x^2=p^2+1^2
or,p^2=x^2-1
or, p=√x^2-1
tan theta=perpendicular/ base
tan theta =√x^2-1/1
tan theta=√x^2-1
z=tan theta
z=√x^2-1
Hope this helps...
Good luck on your assignment..
Just use the formula to find circumference!
C = <span>ᴨd
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