Answer:
decreased genetic variation ( first choice)
Use the Nernst equation which is:
E = E° - (RT/nF)*Ln Q
Where:
E the cell voltage in V,
R the gas constant 8.314 J/K•mol,
T the room temperature normally taken 298.15K, n=3 in this case,
F the Faraday constant 96485C,
Ln is the operation of natural logarithm, and: Q = [Cl-]^3*[Al3+]
Plugging in our values, will give us:
E = 1.88-(8.314*298.15/(3*96485))*Ln(0.010^3...)
= 2.01 (V)
2NaOH + ZnCl2 → 2NaCl + Zn(OH)2
Zn(OH)2 is your precipitate.
No. of moles of NaOH = 2.50X50.0÷1000 = 0.125mol
2mol of NaOH reacted to produce 1 mol of Zn(OH)2.
No. of moles of Zn(OH)2 produced when 0.125mol of NaOH reacted
= 0.125 x 1 ÷ 2
= 0.0625mol
Mass of Zn(OH)2 = 0.0625 x [65.4+2(16+1)] = 6.21g
Ans: The sign of the slope is negative
The free energy change (ΔG) is related to the equilibrium constant Kp as:
ΔG = -RTlnKp -------(1)
Also, ΔG = ΔH-TΔS ------(2)
therefore,
-RTlnKp = ΔH-TΔS
ln(Kp) = -ΔH/R(1/T) + ΔS/R
Thus, a plot of lnKp Vs 1/T will give a straight line with a negative slope such that:
Slope = -ΔH/R
Intercept = ΔS/R
