draw the skeletal structure of the alkyl halide that forms the following alkene as the only product in an elimination reaction.
1 answer:
The alkyl halide that forms the alkene shown as the only product in an elimination reaction is bromomethyl cyclohexane.
An elimination reaction is a reaction in which two atoms are removed to create a double bond. Elimination reaction is a type of reaction that is common to alkyl halides.
In this reaction, a hydrogen atom and a halogen atom are both removed to yield a double bond. The structure of the product depends on the structure of the reactant alkyl halide.
Bromomethylcyclohexane shown in the image attached yields the alkene product in the image attached as the only product when it undergoes elimination reaction.
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The given compound 1,2-dibromo-2-methylbutane is an optically active compound .
Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .
It has chiral center.
Here , the chiral carbon is attached to the 4 distinct groups such as : methyl , ethyl , bromine , bromomethane .
<h3>What is di-symmetry?</h3>Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .
<h3>Chiral center :</h3>Have Sp3 hybridized center (4sigma bond ) .
4 distinct group is attached to the chiral atom. form non -superimposable mirror image .
<h3>What is optical isomerism ?</h3>Same molecular formula and same structural formula . also have same physical and chemical properties .
They differ in their behavior towards plane polarized light (ppl) .
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