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Katyanochek1 [597]
2 years ago
9

draw the skeletal structure of the alkyl halide that forms the following alkene as the only product in an elimination reaction.

you do not need to show lone pairs.
Chemistry
1 answer:
zalisa [80]2 years ago
3 0

The alkyl halide that forms the alkene shown as the only  product in an elimination reaction is bromomethyl cyclohexane.

An elimination reaction is a reaction in which two atoms are removed to create a double bond. Elimination reaction is a type of reaction that is common to alkyl halides.

In this reaction, a hydrogen atom and a halogen atom are both removed to yield a double bond. The structure of the product depends on the structure of the reactant alkyl halide.

Bromomethylcyclohexane shown in the image attached yields the alkene product in the image attached as the only product when it undergoes elimination reaction.

Learn more: brainly.com/question/10609459

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You carefully weigh out 11.00 g of caco3 powder and add it to 44.55 g of hcl solution. you notice bubbles as a reaction takes pl
Zinaida [17]
The bubbles that were observed after the mixing of the two substances is one of the products of the reaction. It is the carbon dioxide that is produced. To determine the mass of this gas produced, we need to remember the Law of conservation of mass where mass cannot be created or destroyed. With this, we can say that the total mass that goes in a process should be equal to the mass that is goes out of the process no matter what the reaction is. We do as follows:

Mass of reactants = mass of products
11.00 + 44.55 = 51.04 + mass of carbon dioxide
mass of carbon dioxide = 4.51 g
8 0
3 years ago
If an object has more positive charges than negative charges, the object has an overall?
guapka [62]
It will have an overall positive charge.
6 0
3 years ago
What is the molarity of a NaCl solution containing 9.0<br> moles of NaCl in 3.0 L of solution?
ss7ja [257]

Answer:

3 M

Explanation:

Molarity equation: M = n/v

n = moles of solute

v = liters of solution

9 moles of NaCl / 3 L

9/3 = 3 M

4 0
3 years ago
The size (radius) of an oxygen molecule is about 2.0 ×10−10m. Make a rough estimate of the pressure at which the finite volume o
belka [17]

Answer:

Explanation:

We can calculate the volume  of the oxygen molecule as the radius of oxygen molecule is given as 2×10⁻¹⁰m.

We know that volume=4/3×πr³

volume =4/3×π(2.0×10⁻¹⁰m)³

volume=33.40×10⁻³⁰m³

Volume of oxygen molecule=33.40×10⁻³⁰m³

we know the ideal gas equation as:

PV=nRT

k=R/Na

R=k×Na

PV=n×k×Na×T

n×Na=N

PV=Nkt

p is pressure of gas

v is volume  of gas

T is temperature of gas

N is numbetr of molecules

Na is avagadros number

k is boltzmann constant =1.38×10⁻²³J/K

R is real gas constant

So to calculate pressure using the  formula;

PV=NkT

P=NkT/V

Since there is only one molecule of oxygen so N=1

P=[1×1.38×10⁻²³J/K×300]/[33.40×10⁻³⁰m³

p=12.39×10⁷Pascal

8 0
3 years ago
Differentiate between <br>Halogens and insert gases​
jasenka [17]

Answer:

An inert gas is one that does not undergo chemical reactions

Noble gases refers to the right most group of the periodic table composed of helium, neon, argon, krypton, xenon, and radon. As you might have seen as an example in class, some noble gases can form chemical compounds, such as XeF4.

or to say:

Halogens and noble gases are two different groups of elements that can be seen on the periodic table. Halogens are found in group 17 and include fluorine, chlorine, bromine, iodine and astatine. Noble gases make up group 18, and include helium, neon, argon, krypton, xenon and radon.

6 0
3 years ago
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