Question

1 2/5m-3/5(2/3m+1) How do you solve this problem

Answer 1

Step-by-step explanation:

I am not sure what you mean by "solve".

I assume you mean simplify the expression.

and then it is very tricky to find the true original expression the way you typed it.

I think you meant

1 2/(5m) - 3/(5(2/(3m + 1)))

1 = 5m/5m

1 2/(5m) = (5m+2)/5m

3/(5(2/(3m + 1))) = 3/(10/(3m + 1)) = 3/1 / (10/(3m + 1))

when dividing by a fraction, it is the same as multiplying with the upside-down fraction

so, this is the same as

3/1 × (3m + 1)/10 = (3(3m + 1)) / (10×1) = (9m + 3)/10

this would give us in total

(5m + 2)/5m - (9m + 3)/10

to do the subtraction we need to bring both fractions to the save denominator (lower part).

it seems to me the easiest one would be 10m.

so,

2×(5m + 2)/10m - m×(9m + 3)/10m =

= (10m + 4)/10m - (9m² + 3m)/10m =

= (10m + 4 - 9m² - 3m)/10m = (-9m² + 7m + 4)/10m

if we want to transform this back to a sum of fractions :

4/10m - (9m² - 7m)/10m = 2/5m - (9m - 7)/10