2 years ago

Point B is on line segment AC. If AB = x + 6, BC = x + 8 and AC = 10, then find the value of x.

1 answer:

7 0

Step-by-step explanation:

this simply means that the sum of both short segments must be the same as the length of the whole line.

so,

x + 6 + x + 8 = 10

2x + 14 = 10

x + 7 = 5

x = 5 - 7 = -2

You might be interested in

Murljashka [212]

Distance of 10 blocks
Displacement of 2 blocks north

8 0

3 years ago

mixas84 [53]

Answer:

91/4

Step-by-step explanation:

3 0

3 years ago

gizmo_the_mogwai [7]

A
Below is how I did it

3 0

3 years ago

Andre45 [30]

In this question, we use law of cosine which is

$RS^2 = RT^2 + ST^2 -2(RT)(ST) cos T$

Substituting the given values of RS,RT, ST , we will get

$3^2 = 5^2 + 7^2 -2(5)(7) cos T \\ 9 = 25 +49 - 70 cos T$

$cos T = \frac{65}{70}$

Taking inverse cosine on both sides

$T = cos^{-1} ( \frac{65}{70})$

$T = 22$

8 0

3 years ago

34kurt

If the area for a box is v=lwh and plugging in the values gives us
v=5*5*5 it is clear that it is 5^3.

7 0

4 years ago