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3 years ago

Combining like terms with negative coefficients −n+(−4)−(−4n)+6

1 answer:

8 0

Remember, if you add negative four, you're really subtracting four, or if you take away negative four, you're really adding four.

-n+(-4)-(-4n)+6
-n-4+4n+6 simplify
{-n+4n are like terms, so combine them. -n+4n is exactly the same as 4n-n, so flip them around if it helps. Just remember to keep the sign with the right number. Same thing with -4+6.}

Answer:

3n+2

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A ball is thrown into the air with an upward velocity of 80ft/s. Its height H in feet after T seconds id given by the function H

pashok25 [27]

1. The function H= -16T^2+80T+5 is a parabola of the form $a x^{2} +bx+c$ , so to find the maximum height of the ball, we are going to find the y-coordinate of the vertex of the parabola. To find the y-coordinate of the vertex we are going to evaluate the function at the point $\frac{-b}{2a}$ .
From our function we can infer that $b=80$ and $a=-16$ , so the point \frac{-b}{2a} [/tex] will be $\frac{-80}{-2(16)} = \frac{5}{2}$ . Lets evaluate the function at that point:
$h=-16t^2+80t+5$
$h=-16( \frac{5}{2} )^2+80( \frac{5}{2} )+5$
$h=105$

We can conclude that the ball reaches a maximum height of 105 feet.

2. Since we now know that the maximum height the ball reaches is 105 feet, we are going to replace $h$ with 105 in our function, then we are going to solve for $t$ to find how long the ball takes to reach its maximum height:
$h=-16t^2+80t+5$
$105=-16t^{2}+80t+5$
$-16t^2+80t-100=0$
$-4(4t^{2}+20t-25)=0$
$4(2t-5)^2=0$
$2t-5=0$
$t= \frac{5}{2}$
$t=2.5$

We can conclude that the ball reaches its maximum height in 2.5 seconds.

3. Just like before, we are going to replace $h$ with 5 in our original function, then we are going to solve for $t$ to find how long will take for the ball to be caught 5 feet off the ground:
$h=-16t^2+80t+5$
$5=-16t^2+80t+5$
$-16t^{2}+80t=0$
$-16t(t-5)=0$
$t-5=0$
$t=5$

We can conclude that it takes 5 seconds for the ball to be caught 5 feet off the ground.

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3 years ago

What is the missing number in this pattern

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3 years ago

I'm an integer. I am less than zero but greater than -13. When you subtract me from -11. The result is positive. What number am

harina [27]

<u>Answer</u><u>: </u>

Required integer is -12.

Step-by-step explanation:

Given:

Required number is integer.

Required integer is less than zero

greater than -13.

When number is substracted from -11, result is positive.

To Find:

The integer=?

Solution:

Lets assume required integer = x

As Required integer is less than zero and greater than -13 ,

-13 < x < 0 ------(1)

Also when number is subtracted from -11, result is positive.

=> -11 – x > 0

=> -11 > x -------(2)

So form 1 and 2

-13 < x < -11 that is x is an integer which is less than -11 and greater than -13. There is only one integer between -13 and -11 that is -12.

Hence required integer is -12.

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3 years ago

Write each word phrase as an algebrale

dedylja [7]

66) ten less than a number

Let the number be n

= n - 10

67) the product of x and y

= x × y or xy

68) The algebraic expression for ten less than n

= n - 10

Must click thanks and mark brainliest

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