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bonufazy [111]
2 years ago
13

Substitution method algebra 1

Mathematics
2 answers:
OlgaM077 [116]2 years ago
7 0

Answer:

<em>x</em> = 3

<em>y</em> = -7

Step-by-step explanation:

<em>y</em> = -4<em>x </em>+ 5

<em>y </em>= 3<em>x </em>- 16

<u>Substitute </u><u><em>y</em></u><u> in the first equation with 3</u><u><em>x</em></u><u> - 16</u>

3<em>x</em> - 16 = -4<em>x </em>+ 5

+4<em>x         </em>+4<em>x</em>

7<em>x</em> - 16 = 5

+16         +16

7<em>x</em> = 21

÷7    ÷7

<em>x</em> = 3

<u>Then, put </u><u><em>x</em></u><u> = 3 in </u><u><em>y</em></u><u> = -4</u><u><em>x</em></u><u> + 5</u>

<em>y</em> = -4(3) + 5

<em>y</em> = -12 + 5

<em>y</em> = -7

tamaranim1 [39]2 years ago
5 0

Answer:

x = 3; y = -7

Step-by-step explanation:

Both equations are solved for y.

Let's substitute what y is equal to in the first equation, -4x + 5, for y in the second equation.

The original second equation is:

y = 3x - 16

Now we plug in -4x + 5 for y in the second equation.

-4x + 5 = 3x - 16

Subtract 3x from both sides.

-7x + 5 = -16

Subtract 5 from both sides.

-7x = -21

Divide both sides by -7.

-7x/-7 = -21/-7

x = 3

Now that we know the value of x, we use substitution again.

Take the first original equation, y = -4x + 5, and substitute 3 for x. Then solve for y.

Here is the first original equation:

y = -4x + 5

Substitute 3 for x:

y = -4(3) + 5

y = -12 + 5

y = -7

The solution is: x = 3; y = -7

We can check the solution to make sure it is correct.

Take each original equation and plug in the values we found for x and y. Simplify both sides and see if they are equal. If the two sides are equal, the solution is correct.

Check first equation:

y = -4x + 5

-7 = -4(3) + 5

-7 = -12 + 5

-7 = -7

The solution works on the first equation.

Check second equation:

y = 3x - 16

-7 = 3(3) - 16

-7 = 9 - 16

-7 = -7

The solution works in the second equation.

This shows that our solution is correct.

Answer: x = 3; y = -7

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