I'm dumb.

A rectangular school banner has a length of 36 inches and a width of 52 inches. A sign is made that is similar to the school ban

zalisa [80]

Answer:

4212 : 1573 is the ratio.

Step-by-step explanation:

Given:

Length of rectangular school banner is 36 inches and width is 52 inches.

And, the sign made is similar to banner.

The sign's length is 22 inches.

Now, we have to find the ratio of the area of the banner to the area of the sign.

So, we have dimensions of rectangular school banner:

Length = 36 inches.

Width = 52 inches.

But, we have only length of sign:

Length = 22 inches.

Now, we have to find the width of sign by using cross multiplication method:

Let the width of sign be $x.$

As, sign is similar to banner.

So, if 36 inches is equivalent to 52 inches.

Then, 22 inches is equivalent to $x.$

$\frac{36}{52} =\frac{22}{x}$

By cross multiplying we get:

$36x=1144$

Dividing both sides by 36 we get:

$x=31\frac{7}{9} .$

Hence, the width of sign is $31\frac{7}{9}$ inches.

Now, we find the area of banner and the area of sign by putting formula:

Area of banner = length × width.

$Area\ of\ banner=36\times 52$

$Area\ of\ banner=1872\ square\ inches.$

Now, area of sign:

$Area\ of\ sign=length\times width\\\\Area\ of\ sign=22\times 31\frac{7}{9} \\\\Area\ of\ sign=22\times \frac{286}{9} \\\\Area\ of\ sign=\frac{6292}{9} \ square\ inches.$

Now, to get the ratio of the area of the school banner to the area of the sign:

$1872:\frac{6292}{9}$

$=\frac{1872}{\frac{6292}{9} } \\\\=\frac{16848}{6292}$

On simplifying we get:

$=\frac{4212}{1573}$

$=4212:1573.$

Therefore, the ratio of the area of the school banner to the area of the sign is 4212:1573.

8 0

2 years ago

3 yards of fabric for $13.47

kumpel [21]

Are you looking for the unit price?

If so, you would divide 13.47 by 3.

This would give you $4.49 per yard.

5 0

3 years ago

Read 2 more answers

. Mr. Perez owns a house on a lot shaped like a square. The perimeter of the lot is 60 feet. What is the length and the width of

pantera1 [17]

Hi there!

If we know the perimeter of the lot, it's pretty easy to find the length and width. Since we know that the lot is a square, we know that all sides are the same. And there are four sides on a square. Using this information, we can get an equation: 60 = x + x + x + x. Then, we need to simplify and solve the equation: 60 = 4x | x = 15 feet. Therefore, the length and width of the lot is 15 feet.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

7 0

3 years ago

Given that A, O & B lie on a straight line segment, evaluate obtuse ∠AOC.

Evgesh-ka [11]

Answer:

AOC = 124°

Step-by-step explanation:

Angle on a straight line is 180°, therefore, the sum of the three angles shown is 180;

This can be written like so:

(3x + 94) + (x + 30) + (2x - 4) = 180

This equation can be solved to find x:

6x + 120 = 180