Answer:
<em>If statement(1) holds true, it is correct that </em>
<em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em><em> is an integer.</em>
<em></em>
Step-by-step explanation:
Given two positive integers 
and 
.
To check whether is an integer:
Condition (1):
Every factor of is also a factor of .
Let us consider an example:
which is an integer.
Actually, in this situation is a factor of .
Condition 2:
Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.
(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)
Let
which is not an integer.
So, the answer is:
<em>If statement(1) holds true, it is correct that </em><em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em><em> is an integer.</em>
<em></em>
Answer:
x = 120
Step-by-step explanation:
Let's draw an imaginary dot in the middle of that <u>line</u> which runs between those two parallel lines, and now lets look at it as an angle.
This lines' angle is 180 degrees. Now lets move those two parallel lines together on the imaginary dot in the middle.
We can see that on the left side is one degree and the other side is another, however when we put them together we get the angle measurement of the our line which we identified was 180.
Now that we can see that our two angles must equal 180 when put together we know and can say that:
40 + (x + 20) = 180
So, lets work this out like basic algebra now.
40 + x + 20 = 180
x + 60 = 180
- 60 - 60
x = 120
And voila we have our x value.
Hope this helps :)
Answer:
Step-by-step explanation:
m∠1+∠2=180
2x+40+2y+40=180
2x+2y=180-80
2x+2y=100
x+y=50
x=50-y
m∠1=m∠3
2x+40=x+2y
2x-x=2y-40
x=2y-40
2y-40=50-y
2y+y=50+40
3y=90
y=30
x=50-y=50-30=20
m∠1=2x+40=2×20+40=80°
m∠2=2y+40=2×30+40=60+40=100°
m∠3=x+2y=20+2×30=80°
Answer:
Distance =√(x₁ - y₁)²+ (x₂ - y₂)² = √97 = 9.85
Step-by-step explanation:
The Matrix X and Y could also be referred to as vectors in Rⁿ dimensions.
if Vector X = ( x₁ , x₂) and Vector Y = (y₁ , y₂)
then, Distance (X-Y) = ||X-Y|| = √(x₁ - y₁)²+ (x₂ - y₂)²
where, x₁ = 8, x₂ = -5 and y₁ = -1 , y₂ = -9
Distance = √(8 - (-1))²+ (-5 - (-9))² = √9² + 4² =√97 = 9.85
Answer:
- 2.25/3
Step-by-step explanation:
